Answer:
y = -3/5x - 12/5
Step-by-step explanation:
The equation I'm going to give is going to be in slope-intercept form. If you need it in point-slope, I can do so in an edit or the comments.
Slope-intercept form is: <em>y = mx + b</em> where m is the slope, b is the y-intercept.
So let's plug in our given slope:
y = -3/5x + b
Using this, we now plug in our x- and y-coordinates from the given point to solve for b.
-3 = -3/5(1) + b
-3 = -3/5 + b
Add 3/5 to both sides to isolate variable b.
-3 + 3/5 = b
-15/5 + 3/5 = b
-12/5 = b
Plug this new info back into the original equation and your answer is
y = -3/5x - 12/5
The answer is 2 radical 3
Hello:<span>
the equation is : y = ax+b
the slope is a : a×(-3/2) = -1......(
perpendicular to a line with a slope of -3/2)
a = 2/3 y=(2/3)x+b
the line that passes through (-2, -2) :- 2 =
(2/3)(-2)+b
b = -2/3
<span> the equation is : y = (2/3)x-2/3</span></span>
<span><span>y =(2/3)(x-1)</span></span>
A cosine is just a sine shifted to the left by π/2. A cosine of 4x is shifted to the left by only π/8 because of the factor 4. Sketch them.
The region we're looking for is this sausage-shaped part between the cos and the sin.
The x intercepts are at π/8 for the cosine and π/4 for the sine. The midpoint between them is at (π/8 + π/4)/2 = 3/16π.
The region is point symmetric around the x axis, so the y coordinate of the centroid is 0.
So the centroid is at (3/16π, 0)
When you evaluate the expression “12 more than 5” you would get the product of 60.
