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Magnetic resonance imaging needs a magnetic field strength of 1.5 T. The solenoid is 1.8 m long and 75 cm in diameter. It is tig

pogonyaev

Answer:

The current needed is 1790.26 A

Explanation:

Given;

magnitude of magnetic field, B = 1.5 T

length of the solenoid, L = 1.8 m

diameter of the solenoid, d = 75 cm = 0.75 m

The magnetic field is given by;

$B = \frac{\mu_o NI }{L}$

Where;

μ₀ is permeability of free space = 4π x 10⁻⁷ m/A

I is current in the solenoid

N is the number of turns, calculated as;

$N = \frac{Length \ of\ solenoid}{diameter \ of \ wire} \\\\N = \frac{1.8}{1.5*10^{-3}} =1200 \ turns$

The current needed is calculated as;

$I = \frac{BL}{\mu_o N} \\\\I = \frac{1.5 *1.8}{4\pi *10^{-7} *1200} \\\\I = 1790.26 \ A$

Therefore, the current needed is 1790.26 A.

8 0

3 years ago

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A copper rod 81 cm long is used to poke a fire. the hot end of the rod is maintained at 105° c and the cool end has a constant t

Ugo [173]

The temperature inside the copper rod varies linearly with the distance from the hot end of the rod. This means that we can find the temperature at 23 cm (let's call it 'point A') from the cool end by solving a linear proportion.

The temperature difference between the two ends of the rod is
$\Delta T = 105^{\circ}-21^{\circ} = 84^{\circ}$
and this corresponds to a length of 81 cm. Therefore, we can write:
$84^{\circ}:81~cm = x:23~cm$
from which we find
$x=23.8~^{\circ}$
This is not the final answer actually; this is the temperature difference between the cool end and point A. So, the temperature at point A is
$T_A = 21^{\circ}+x=44.8^{\circ}$

7 0

2 years ago

Jocelyn is running for the U.S Senate. What is one of the qualifications for office she must meet?

VMariaS [17]

Answer:

b

Explanation:

4 0

2 years ago

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A block weighing 30kg is moved at a constant speed over a horizontal surface by a force of 100 N applied parallel

DENIUS [597]

30-100=70^3•É+ 30 =3^E

5 0

2 years ago

a lorry travels 3600m on a test track accelerating constantly at 3m/s squared from standstill. what is the final velocity (3 sig

suter [353]

The final velocity of the truck is found as 146.969 m/s.

Explanation:

As it is stated that the lorry was in standstill position before travelling a distance or covering a distance of 3600 m, the initial velocity is considered as zero. Then, it is stated that the lorry travels with constant acceleration. So we can use the equations of motion to determine the final velocity of the lorry when it reaches 3600 m distance.

Thus, a initial velocity (u) = 0, acceleration a = 3 m/s² and the displacement s is 3600 m. The third equation of motion should be used to determine the final velocity as below.

$2as =v^{2} - u^{2} \\\\v^{2} = 2as + u^{2}$

Then, the final velocity will be

$v^{2} = 2 * 3 * 3600 + 0 = 21600\\ \\v=\sqrt{21600}=146.969 m/s$

Thus, the final velocity of the truck is found as 146.969 m/s.

8 0

3 years ago