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Delicious77 [7]
3 years ago
12

What does each letter stand for in the formula p=v x i?

Physics
1 answer:
Nataly_w [17]3 years ago
6 0
I only know P and V and P is pressure and V is volume 
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A joger travels 8.0 kilometers in 1.25 hours what is the average speed?
Svetach [21]
ΔS  = 8.0 km

ΔT = 1.25 h

Vm  =  ΔS / ΔT

Vm = 8.0 / 1.25

Vm = 6.4 Km/h

hope this helps!
3 0
3 years ago
Read 2 more answers
An object originally at rest, is accelerated uniformly along a straight line to a speed of 8m/s in 2s. What is the acceleration
Anna11 [10]

Answer:

4m/s²

Explanation:

Initial velocity (u) = 0 m/s

Final velocity (v) = 8 m/s

Time taken (t) = 2 sec

Acceleration (a) = ?

We know

a  =  \frac{v - u}{t}  \\  =  \frac{8 - 0}{2} \\  =  \frac{8}{2}  \\  = 4 \: m |s ^{2}

Hope it will help :)

3 0
3 years ago
A 15 kg mass is lifted to a height of 2m. What is gravitational potential energy at this position
7nadin3 [17]

Answer: 294J

Explanation:

U_g=mg(y_f-y_i)

U_g=(15)(9.8)(2-0)=294J

7 0
3 years ago
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A solenoid has 332 turns and a length of 14 cm. If a current of 0.88 A produces a magnetic flux density of 0.28 T in the core of
irina1246 [14]

Answer:

106.83

Explanation:

N = 332, l = 14 cm = 0.14 m, i = 0.88 A, B = 0.28 T

Let ur be the relative permeability

B = u0 x ur x n x i

0.28 = 4 x 3.14 x 10^-7 x ur x 332 x 0.88 / 0.14       ( n = N / l)

ur = 106.83

3 0
3 years ago
What would be your estimate of the age of the universe if you measured a value for Hubble's constant of H0 = 30 km/s/Mly ? You c
Maksim231197 [3]

Answer:

The age of the universe would be 9.9 billion years

Explanation:

We can calculate an estimate for the age of the Universe from Hubble's Law. Let's suppose the distance between two galaxies is D and the apparent velocity with which they are separating from each other is v. At some point, the galaxies were touching, and we can consider that time the moment of the Big Bang.

Thus, the time it has taken for the galaxies to reach their current separations is:

\displaystyle{t=D/v}

and from Hubble's Law:

v =H_0D

Therefore:

\displaystyle{t=D/v=D/(H_0\times D)=1/H_0}

With the given value for the Hubble's constant we have:

H_0=(30\ km/s/Mly) \times (1 Mly/ 9.461 \times 10^{18} km) = 3.17\times 10^{-18}\ 1/s

and thus,

t=1/H_0 = 1/(3.17\times 10^{-18} 1/s) = 0.315 \times 10^{18}\ s \approx 9988584474.8858\ years \approx 9.9\ billion\ years

6 0
3 years ago
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