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larisa [96]
3 years ago
12

ListenA bicycle and its rider have a combined mass of 80. kilograms and a speed of 6.0 meters per second. What is the magnitude

of the average force needed to bring the bicycle and its rider to a stop in 4.0 seconds?
a.1.2 × 102 N
b.3.2 × 102 N
c.4.8 × 102 N
d.1.9 × 103 N
Physics
1 answer:
Setler [38]3 years ago
3 0

Answer:

a) 1.2\times 10^2\ N

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

a = Acceleration

v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{0-6}{4}\\\Rightarrow a=-1.5\ m/s^2

The acceleration of the bicycle and rider is -1.5 m/s²

Force

F=ma\\\Rightarrow F=80\times -1.5\\\Rightarrow F=-120\ N=-1.2\times 10^2\ N

The magnitude of the average force needed to bring the bicycle and its rider to a stop is 1.2\times 10^2\ N

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A 25 kg circular disk has a diameter of 2.5 feet and a thickness of 2.5 cm. Find the density of the disk in kg/m3. Next, find th
Gre4nikov [31]

Answer:

Assume that \rm g= 9.81\; N\cdot kg^{-1}; \rho(\text{Water}) = \rm 1000\;kg\cdot m^{-3}.

Density of the disk: approximately \rm 2.19\times 10^{3}\; kg\cdot m^{-3}.

Weight of the disk: approximately \rm 245\;N.

Buoyant force on the disk if it is submerged under water: approximately \rm 112\; N.

The disk will sink when placed in water.

Explanation:

Convert the dimensions of this disk to SI units:

  • Diameter: d = \rm 25\; inches = (25\times 0.3048)\; m = 0.762\;m.
  • Thickness h = \rm 2.5\; cm = (2.5\times 0.01)\; m = 0.025\;m.

The radius of a circle is 1/2 its diameter:

\displaystyle r = \rm \frac{1}{2}\times 0.762\;m = 0.381\; m.

Volume of this disk:

V(\text{disk}) = \pi\cdot r^{2}\cdot h = \pi\times 0.381^{2}\times 0.025 \approx 0.0114009\; m^{3}.

Density of this disk:

\displaystyle \rho(\text{disk}) = \frac{m}{V} = \rm \frac{25\; kg}{0.0114009\; m^{3}} = 2.19\times 10^{3}\;kg\cdot m^{-3}.

\rho(\text{disk}) >\rho(\text{water}) indicates that the disk will sink when placed in water.

Weight of the object:

W(\text{disk}) = m\cdot g = \rm 25\times 9.81 = 245.25\; N.

The buoyant force on an object in water is equal to the weight of water that this object displaces. When this disk is submerged under water, it will displace approximately \rm 0.0114009\; m^{3} of water. The buoyant force on the disk will be:

\begin{aligned}F(\text{buoyant force}) &= W(\text{Water Displaced}) \\& = \rho\cdot V(\text{Water Displaced})\cdot g\\ & = \rm 1\times 10^{3}\; kg\cdot m^{-3}\times 0.0114009\; m^{3}\times 9.81\; N\cdot kg^{-1}\\ &\approx \rm 112\; N\end{aligned}.

The size of this disk's weight is greater than the size of the buoyant force on it when submerged under water. As a result, the disk will sink when placed in water.

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3 years ago
What mass of a material with density ρ is required to make a hollow spherical shell having inner radius r1 and outer radius r2?
krok68 [10]

Answer: m=\frac {\rho}{\frac{4}{3} \pi( (r_2)^{3} - (r_1)^{3}) }

It is given that:

Density of material =ρ

radius of inner spherical shell = r_1

radius of outer spherical shell=r_2

we know that the volume of sphere is \frac{4}{3}\pi r^{3}

Volume of the given spherical shell = \frac{4}{3}\pi( (r_2)^{3}-(r_1)^{3})

Then mass of the spherical shell can be calculate as:

Mass, m=density/ volume

m=\frac {\rho}{\frac{4}{3} \pi ((r_2)^{3} - (r_1)^{3}) }


6 0
3 years ago
KI + Cl2 ---&gt; KCl + I2<br> Balance the single replacement chemical reaction.
snow_lady [41]

Answer:

2KI   +  Cl₂   →   2KCl     +    I₂

Explanation:

The reaction equation is given as:

        KI   +  Cl₂   →    KCl     +    I₂

The problem at hand is to balance this chemical reaction. To solve this problem we use a mathematical approach;

        aKI   +  bCl₂   →    cKCl     +    dI₂

 Conserving K : a = c

                     I :  a  = 2d

                   Cl : 2b = c  

 Now let a = 1, c  = 1 , d  = \frac{1}{2}, b   = \frac{1}{2}, ;

   Multiply through by 2;

             a  = 2, b = 1 , c = 2, d  = 1

 

            2KI   +  Cl₂   →   2KCl     +    I₂

 

5 0
3 years ago
The coefficient of static friction between a book and the level surface it slides on is 0.65. If the mass of the book is 0.2 kg,
just olya [345]

Answer: 1.274 N minimum force required to slide the book across the surface

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Minimum force required to slide the book across the surface= F

F=\mu_s\times N

F=0.65\times 0.2 kg\times 9.8 m/s^2=1.274 N

1.274 N minimum force required to slide the book across the surface

7 0
3 years ago
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3. If atoms are mostly empty space, why can't<br> we walk through walls?
Serhud [2]

Answer:

Good question

Explanation:

The reason is that walls are made up of more than just atoms. Walls are built up from many things, so with this being said we cannot walk through the walls

PPs why do or should anyone want to walk through walls?

7 0
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