Answer:
L/2
Explanation:
Neglect any air or other resistant, for the ball can wrap its string around the bar, it must rotate a full circle around the bar. This means the ball should be able to swing to the top position where it's directly above the bar. By the law of energy conservation, this happens when the ball is at the same level as where it's previously released vertically. It means the swinging radius around the bar must be at least half of the string length.
So the distance d between the bar and the pivot should be at least L/2
travel through a vacuum at the speed of light. Other waves need a medium; sound waves need molecules that vibrate.
Answer:
v = 344.1 m / s
d = 1720.5 m
Explanation:
For this problem we must calculate the speed of sound in air at 22ºC
v = 331 RA (1+ T / 273)
we calculate
v = 331 RA (1 + 22/273)
v = 344.1 m / s
the speed of the wave is constant,
v = d / t
d = v t
we calculate
d = 344.1 5
d = 1720.5 m
Answer:
1500 milliradians
Explanation:
Data provided in the question:
1.5 radians
Now,
1 radians consists of 1000 milliradians
1 milli = 1000
thus for the 1.5 radians, we have
1.5 radians = 1.5 multiplied by 1000 milliradians
or
1.5 radians = 1500 milliradians
Hence, after the conversion
1.5 radians equals to the value 1500 milliradians