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Name all of the alkene isomers, c6h12, that contain a methylene group.

Romashka [77]

Actually, a methylene group is simply any compound which contains a C=C double bond group and the rest are single bonded carbon groups. Some example of the isomers of C6H12 which contains methylene group is:

1-hexene

2,3-dimethyl-2-butene

2,3-dimethyl-1-butene

2-methyl-2-pentene

trans-2-hexene

4-methyl-1-pentene

cis-2-hexene

trans-3-hexene

2-ethyl-1-butene

2-methyl-1-pentene

3,3-dimethyl-1-butene

4-methyl-cis-2-pentene

cis-3-methyl-2-pentene

trans-3-methyl-2-pentene

4 0

4 years ago

What was one of the first series of event in the study of chemistry

baherus [9]

Discovered and isolated radium and polonium in 1898

7 0

3 years ago

A venti latte (502mL) contains 0.322g caffeine, C8H10N4O2, express this concentration in molarity.

Natalija [7]

Answer:

0.00331M

Explanation:

Molarity of a solution can be calculated as follows:

Molarity = number of moles (n) ÷ volume (V)

In the information provided in this question, the volume = 502mL = 502/1000 = 0.502L, mass of caffeine = 0.322g

Molar mass of caffeine (C8H10N4O2), where C = 12, H = 1, N = 14, O = 16 is as follows:

Molar mass = 12(8) + 1(10) + 14(4) + 16(2)

= 96 + 10 + 56 + 32

= 194g/mol

Using, moles = mass/molar mass

moles = 0.322/194

moles = 1.66 × 10-³ moles

mole = 0.00166mol

Molarity = number of moles ÷ volume

Molarity = 0.00166mol ÷ 0.502L

Molarity = 0.00331M.

7 0

3 years ago

You need to prepare 250.0 mL of a 1.35 M HCl solution from a 2.00 M HCl stock solution.

Lyrx [107]

Answer:

a. C. volumetric flask

b. B. Measure out x mL using a volumetric pipet

c. 168.75mL

d. B. Add the correct amount of stock solution then fill to the 250 mL mark with water.

Explanation:

The volumetric flask is mainly used in analytical chemistry to contain standard solutions or to prepare dilutions of a certain concentration of a reagent.
The volumetric pipette is used to deliver a given volume with greater precision and accuracy.
To make a dilution, the formula C1*V1 = C2*V2 is used where C is the concentration of the solution, in this case of molarity. V is the volume of the solution in ml and terms 1 and 2 correspond to the concentrated and diluted solutions respectively.

$V2=\frac{1.35M*250mL}{2.00M} =168.75mL$

8 0

4 years ago

The thallium Subscript 81 Superscript 208 Baseline Tl nucleus is radioactive, with a half-life of 3.053 min. At a given instant,

Genrish500 [490]

Answer: (E) 300 bq

Explanation:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

Radioactive decay process is a type of process in which a less stable nuclei decomposes to a stable nuclei by releasing some radiations or particles like alpha, beta particles or gamma-radiations. The radioactive decay follows first order kinetics.

Half life is represented by $t_{\frac{1}{2}$

Half life of Thallium-208 = 3.053 min

Thus after 9 minutes , three half lives will be passed, after ist half life, the activity would be reduced to half of original i.e. $\frac{2400}{2}=1200$ , after second half life, the activity would be reduced to half of 1200 i.e. $\frac{1200}{2}=600$ , and after third half life, the activity would be reduced to half of 600 i.e. $\frac{600}{2}=300$ ,

Thus the activity 9 minutes later is 300 bq.

7 0

3 years ago