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Lelu [443]
3 years ago
8

What's the answer for this question please thank you :)​

Mathematics
1 answer:
vova2212 [387]3 years ago
7 0

Answer:

Arc AB = 110

Step-by-step explanation:

<C = 55 degrees. That's the way the triangle is marked. AB = BC.

The central angle is twice the angle made by the end points of line AB

The central angle = 2*55 = 110

The measure of arc AB equals the central angle which makes arc AB = 110

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7 1/8 is greater than 7.025
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3 years ago
Plz plz ans this with explanation
saveliy_v [14]

Answer:

8750

Step-by-step explanation:

Since the random sample contained 125 out of 500 people who voted for the dog park that is about 25%. since 25% of 500 is 125. If we scale that up to 25% of 3500 it would be 8750 people.

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3 years ago
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How do you distinguish between multiples and factors of a number, and justify your evaluation of the LCM &amp; GCF of a set of n
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Answer:

Look to the explanation

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- <u><em>Lowest common multiple of the set of numbers (LCM)</em></u> is the

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- <u><em>Greatest common factor of the set of numbers (GCF)</em></u> is the highest

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- Ex: The greatest common factor of 12 and 18 is 6 because

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→ The greatest common factor on both numbers is 6

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4 years ago
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2 years ago
Given: BD bisects ABC. Auxiliary EA is drawn such that AE || BD. Auxiliary BE is an extension of BC
AnnZ [28]
The required proof is given in the table below:

\begin{tabular}{|p{4cm}|p{6cm}|} &#10; Statement & Reason \\ [1ex] &#10;1. $\overline{BD}$ bisects $\angle ABC$ & 1. Given \\&#10;2. \angle DBC\cong\angle ABD & 2. De(finition of angle bisector \\ &#10;3. $\overline{AE}$||$\overline{BD}$ & 3. Given \\ &#10;4. \angle AEB\cong\angle DBC & 4. Corresponding angles \\&#10;5. \angle AEB\cong\angle ABD & 5. Transitive property of equality \\ &#10;6. \angle ABD\cong\angle BAE & 6. Alternate angles&#10;\end{tabular}
\begin{tabular}{|p{4cm}|p{6cm}|}&#10;7. \angle AEB\cong\angle BAE & 7. Transitive property of equality \\&#10;8. \overline{EB}\cong\overline{AB} & 8. From 7. $\Delta ABE$ is isosceles \\&#10;9. EB = AB & 9. De(finition of congruence \\ 10. $\frac{AD}{DC}=\frac{EB}{BC}$ & 10. Triangle proportionality theorem \\&#10;11. $\frac{AD}{DC}=\frac{AB}{BC}$ & 11. Substitution Property of equality \\[1ex] &#10;\end{tabular}&#10;
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