Answer:
is the total displacement (volume) of the submarine.
Explanation:
Mass of water carried by submarine at 1000 ft depth = m = 2100 kg
The density of seawater at 1000 ft depth = d = 
Volume of the water displaced = V= ?
Total displacement of the submarine = Volume of the water displaced = V


is the total displacement (volume) of the submarine.
Answer: i believe it is
602,000,000,000,000,000,000,000 atoms
Explanation:
6.02×1023 atoms/mole
It is "LICI" I believe. I could be wrong please let me know if I am wrong.
The number of electrons when the quantum number n=2 is 8 electrons. Variab<span>le </span>n<span> represents the principal quantum number which is the number of the energy level. </span>
1Draw a quick sketch of the object.
2Draw an arrow showing every force acting on the object.
3To calculate the net force, add any vectors acting on the same axis (x and y), making sure to pay attention to the directions.