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sattari [20]
3 years ago
12

An iron object alloyed with cobalt rusts more quickly than a pure iron object. However, an iron object alloyed with manganese ru

sts less quickly than a pure iron object under the same conditions. This is true because: __________
a. cobalt is a stronger reducing agent than iron
b. iron is a stronger reducing agent than manganese
c. cobalt exhibits more metallic character than either iron or manganese in the iron-manganese alloy
Chemistry
1 answer:
HACTEHA [7]3 years ago
5 0

Rusting is an electrochemical reaction. Iron rusts faster when alloyed with cobalt than when alloyed with manganese because, in the iron-manganese alloy, manganese is rendered the anode and iron is rendered the cathode

An alloy is a combination of two metals. There are various reasons for producing alloys such as greater tensile strength, corrosion resistance and improved aesthetic appearance.

When iron is alloyed with cobalt, the iron rusts faster than pure iron because iron is rendered the anode and cobalt is rendered the cathode. When the iron is alloyed with manganese, it rusts more slowly than pure iron because in the iron-manganese alloy, manganese is rendered the anode and iron is rendered the cathode.

Missing parts;

An iron object alloyed with cobalt rusts more quickly than a pure iron object. However, an iron object alloyed with manganese rusts less quickly than a pure iron object under the same conditions. This is true because

(1) cobalt is a stronger reducing agent than iron

(2) iron is a stronger reducing agent than manganese

(3) cobalt exhibits more metallic character than either iron or manganese

(4) in the iron-manganese alloy, manganese is rendered the anode and iron is rendered the cathode

(5) in the iron-cobalt alloy, cobalt is rendered the anode and iron is rendered the cathode

Learn more: brainly.com/question/14281129

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I really hope this helps! I wish you the best of luck!

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The concentration of carbon monoxide (CO), a common air pollutant, is found in a room to be 5.7 x 10^-3 mg/cm^3. How many grams
damaskus [11]

The amount, in mg, of CO present in the room will be 191,520 mg.

<h3>Stoichiometric problem</h3>

The concentration of the gas in the room is 5.7 x 10^{-3} mg/cm3.

The dimension of the room is 3.5 m x 3.0 m x 3.2 m. This is equivalent to 350 cm x 300 cm x 320 cm.

We can obtain the volume of the room as:

                  350 x 300 x 320 = 33,600,000 cm3

The concentration is in mg/cm3, meaning that it is mass/volume.

Thus:

 mass = concentration x volume = 5.7 x 10^{-3} mg/cm3 x 33,600,000 cm3

                         = 191,520 mg

The mass of CO in the room is 191,520 mg

More on stoichiometric problems can be found here: brainly.com/question/14465605

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