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Furkat [3]
3 years ago
10

If 2 objects have the same volume, but one has more mass than the other, are the densities the same or different? Explain

Chemistry
1 answer:
laiz [17]3 years ago
4 0

The one with higher mass has a higher density because it fits more mass into the same amount of space (volume).

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Beverly and Carl are in a race. Their graphs show the data.
Nikitich [7]

Given the data, the correct statement is

Even though for a majority of the race they accelerated at the same rate, Beverly won because her initial acceleration was greater than Carl’s

<h3>What is acceleration? </h3>

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

  • a is the acceleration
  • v is the final velocity
  • u is the initial velocity
  • t is the time

<h3>How to determine the initial acceleration of Beverly</h3>
  • Initial velocity (u) = 0 m/s
  • Final velocity (v) = 15 m/s
  • Time (t) = 10 s
  • Initial acceleration (a₁) =?

a₁ = (v – u) / t

a₁ = (15 – 0) / 10

a₁ = 1.5 m/s²

<h3>How to determine the final acceleration of Beverly</h3>
  • Initial velocity (u) = 15 m/s
  • Final velocity (v) = 35 m/s
  • Time (t) = 50 - 10 = 40 s
  • Final acceleration (a₂) =?

a₂ = (v – u) / t

a₂ = (35 – 15) / 40

a₂ = 0.5 m/s²

<h3>How to determine the initial acceleration of Carl</h3>
  • Initial velocity (u) = 0 m/s
  • Final velocity (v) = 10 m/s
  • Time (t) = 10 s
  • Initial acceleration (a₁) =?

a₁ = (v – u) / t

a₁ = (10 – 0) / 10

a₁ = 1 m/s²

<h3>How to determine the final acceleration of Carl</h3>
  • Initial velocity (u) = 10 m/s
  • Final velocity (v) = 30 m/s
  • Time (t) = 50 - 10 = 40 s
  • Final acceleration (a₂) =?

a₂ = (v – u) / t

a₂ = (30 – 10) / 40

a₂ = 0.5 m/s²

SUMMARY

  • Initial acceleration of Beverly = 1.5 m/s²
  • Final acceleration of Beverly = 0.5 m/s²
  • Initial acceleration of Carl = 1 m/s²
  • Final acceleration of Carl = 0.5 m/s²

From the above calculations, we can see that Beverly's initial acceleration is higher than that of Carl's and their final acceleration is the same.

Therefore, the correct answer to the question is:

Even though for a majority of the race they accelerated at the same rate, Beverly won because her initial acceleration was greater than Carl’s

Complete question

See attached photo

Learn more about acceleration:

brainly.com/question/491732

#SPJ1

8 0
2 years ago
(True or false) The water molecule can be either an acid or a base. Justify.
iren [92.7K]

Answer:

TRUE!!!!

Explanation:

Water can act as both an acid and a base in solution and undergoes autoionization, where it can be both an acid and a base to itself. When mixed with an acid, water accepts hydrogen ions and acts as a base. However, when water is mixed with a base, it donates hydrogen ions and acts like an acid.

Not my words! I hope this helps :)

6 0
3 years ago
Read 2 more answers
Consider the following reaction mechanism:
snow_lady [41]

Answer:

  • <em><u>Step 2 (the slow step).</u></em>

Explanation:

The rate-determining step is always the slow step of a mechanism.

That is so, because it is the slow step which limits the reaction.

Imaging that for assembling a toy you have process of three steps:

  • 1. order ten pieces, which you can do in 1 minute: meaning that you can order order the pieces for 60/1 = 60 toys in 1 hour.

  • 2. glue the pieces and hold the toy until the glue hardens, which takes 1 hour: meaning finishingh 1 toy in 1 hour.

  • 3. pack the toy, which takes 2 minutes: meaning that you can pack 60/2 = 30 toys in one hour.

The time to glue and hold one toy until the glue hardens determines that you can assemble 1 toy in 1 hour and not 60 toys or 30 toys.

Thus, the step that determines the rate at which the reaction happens is the slowest step: step 2.

3 0
3 years ago
Read 2 more answers
Products and reactants are used and created at the same rate when a reaction is at this stage
V125BC [204]

This means that the reaction is in dynamic equilibrium.

Hope this helps because I don't really know the question you asked :)))

7 0
4 years ago
Read 2 more answers
The gas inside a balloon exerts a pressure of 3atm at 298 K. What is the temperature required to increase the pressure to 6 atm?
podryga [215]

Answer: 596 atm

Explanation:

Given that,

Original pressure of balloon P1 = 3atm

Original temperature of balloon T1 = 298K

New pressure of balloon P2 = 6atm

New temperature of balloon T2 = ?

Since pressure and temperature are given while volume is constant, apply the formula for Pressure law

P1/T1 = P2/T2

3 atm / 298K = 6 atm / T2

To get the value of T2, cross multiply

3 atm x T2 = 6 atm x 298K

3 atmT2 = 1788 atmK

Divide both sides by 3 atm

3 atmT2 / 3 atm = 1788 atmK / 3 atm

T2 = 596 atm

Thus, a temperature of 596 atmospheres is required to increase the pressure to 6 atm.

7 0
3 years ago
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