What would be the water potential of pure water at atmospheric pressure?
1 answer:
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Answer: Volume of the gas at STP is 22.53 L.
Explanation:
Given : Volume = 125 mL (as 1 mL = 0.001 L) = 0.125 L
Temperature =
Pressure =
According to the ideal gas equation, the volume of given nitrogen gas is calculated as follows.
PV = nRT
where,
P = pressure
V = volume
n = number of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
Hence, volume of the gas at STP is 22.53 L.
Answer : The excess reactant is,
The leftover amount of excess reagent is, 7.2 grams.
Solution : Given,
Mass of = 105.0 g
Mass of = 78.0 g
Molar mass of = 80.11 g/mole
Molar mass of = 18 g/mole
Molar mass of = 100.09 g/mole
First we have to calculate the moles of and
.
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 1 mole of react with 3 mole of
So, 1.31 moles of react with
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Left moles of excess reactant = 4.33 - 3.93 = 0.4 moles
Now we have to calculate the mass of excess reactant.
Thus, the leftover amount of excess reagent is, 7.2 grams.