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2 years ago

Omar's cats claws grow 1/8 in in 1/12 of a year which is the amount of cats claws will grow in one year

Mathematics

2 answers:

Lyrx [107]2 years ago

8 0

So 1/8 per month
1/8 * 12 months = 3/2
Reduced is 1 1/2 inches per year

4vir4ik [10]2 years ago

5 0

Answer:

1 1/2

Step-by-step explanation:

I got it right

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If f(x) = 3x + 2 and

Butoxors [25]

Answer:

Step-by-step explanation:

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2 years ago

In quadrilateral ABCD,AB produced is perpendicular to DC produced.If A=44° and C=148°,calculate D and B.

7nadin3 [17]

Let AB extended intersect DC extended at point E
We now have right triangle BEC with E = 90 degrees 

For triangle BEC: 
Exterior angle at E = 90 
Exterior angle at C = 148 (given) 
Exterior angle of all polygons add up to 360 degrees 
Exterior angle at B = 360−148−90 = 122 

So in quadrilateral ABCD 
B = 122 
D = 360−44−148−122 = 46

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3 years ago

Two collinear points on a line are given in the table below:

katrin [286]

Answer:

$(4,3)$ and $(7,2)$ do not lie on the line

Step-by-step explanation:

Given

$(0,0)\ and\ (2,1)$

Required

Determine which points that are not on the line

First, we need to determine the slope (m) of the line:

$m = \frac{y_2 - y_1}{x_2- x_1}$

Where

$(x_1,y_1) = (0,0)$

$(x_2,y_2) = (2,1)$

So;

$m = \frac{y_2 - y_1}{x_2- x_1}$

$m = \frac{1 - 0}{2-0}$

$m = \frac{1}{2}$

Next, we determine the line equation using:

$y - y_1 = m(x -x_1)$

Where

$m = \frac{1}{2}$

$(x_1,y_1) = (0,0)$

$y - y_1 = m(x -x_1)$ becomes

$y - 0 = \frac{1}{2}(x - 0)$

$y = \frac{1}{2}x$

To determine which point is on the line, we simply plug in the values of x to in the equation check.

For $(4,2)$

$x = 4$ and $y =2$

Substitute 4 for x and 2 for y in $y = \frac{1}{2}x$

$2 = \frac{1}{2} * 4$

$2 = \frac{4}{2}$

$2=2$

This point is on the graph

For $(4,3)$

$x = 4$ and $y = 3$

Substitute 4 for x and 3 for y in $y = \frac{1}{2}x$

$3 = \frac{1}{2} * 4$

$3 = \frac{4}{2}$

$3 \neq 2$

This point is not on the graph

For $(7,2)$

$x = 7$ and $y = 2$

Substitute 7 for x and 2 for y in $y = \frac{1}{2}x$

$2 = \frac{1}{2} * 7$

$2 = \frac{7}{2}$

$2 \neq 3.5$

This point is not on the graph

$(\frac{4}{8},\frac{2}{8})$

$x = \frac{4}{8}$ and $y = \frac{2}{8}$

Substitute $\frac{4}{8}$  for x and  $\frac{2}{8}$ for y in $y = \frac{1}{2}x$

$\frac{2}{8} = \frac{1}{2} * \frac{4}{8}$

$\frac{2}{8} = \frac{1 * 4}{8 * 2}$

$\frac{2}{8} = \frac{4}{16}$

$\frac{1}{4} = \frac{1}{4}$

This point is on the graph

3 0

3 years ago

What is the answer to this problem using distributive property. 7 × 43 =

insens350 [35]

Answer: 301

Step-by-step explanation:

6 0

3 years ago

A company that makes hard candy have a standard bag of hard candy with 150 pieces. The hard candy has three distinct colors red,

anzhelika [568]

Answer:

The degrees of freedom, Df = The number of bags produced on Monday - 1

Step-by-step explanation:

The number of degrees of freedom is the limiting number of values that are logically not influenced by other values such that they are capable of having variation

The degrees of freedom = The sample size - 1 = N - 1

Therefore, the degrees of freedom, Df = The number of bags produced on Monday - 1

5 0

2 years ago

Omar's cats claws grow 1/8 in in 1/12 of a year which is the amount of cats claws will grow in one year​

Omar's cats claws grow 1/8 in in 1/12 of a year which is the amount of cats claws will grow in one year