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Maurinko [17]
3 years ago
11

Precision Problems:

Chemistry
1 answer:
Lorico [155]3 years ago
4 0

Answer:

Precision = 2.70 \± 0.1\ cm

Explanation:

Given

The data in the table

Required

Follow the steps appended to the question;

Step 1: Calculate the Mean or Average

Mean = Summation of lengths divided by number of teams;

Mean = \frac{2.65 + 2.75 + 2.80 + 2.77 + 2.60 + 2.65 + 2.68}{7}\ cm

Mean = \frac{18.9}{7}\ cm

Mean = 2.70\ cm

Step 2: Get The Range

Range = Highest - Lowest

Range = 2.80cm - 2.60cm

Range = 0.2\ cm

Step 3: Divide Range by 2

Approximate\ Range = \frac{1}{2}Range

Approximate\ Range = \frac{1}{2} * 0.2\ cm

Approximate\ Range = 0.1\ cm

Step 4: Determine the Precision

Precision = Average \± Approximate\ Range

Substitute 2.70 for Average and 0.1 for Approximate Range

Precision = 2.70 \± 0.1\ cm

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Given that solubility product of AgCl = 1.8 X 10^-10

Dissociation of AgCl can be represented as follows,

AgCl(s)             ↔      Ag+(ag)             +           Cl-(aq)

Let, [Ag+] = [Cl-] = S

∴Ksp = [Ag+][Cl-] = S^2

∴ S = √Ksp = √(1.8 X 10^-10) = 1.34 x 10^-5 mol/dm3

Now, Molarity of solution = \frac{\text{weight of solute}}{\text{Molecular weight X volume of solution (l)}}
              ∴  1.34 x 10^-5     = \frac{\text{weight of AgCl}}{143.4 X 1}
∴ Weight of AgCl present in solution = 1.92 X 10^-3 g

Thus, mass of AgCl that will dissolve in 1l water = 1.92 x 10^-3 g
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What substance and mixture have in common?
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En condiciones normales 1g de aire ocupa un volumen de 773 mL ¿ qué volumen ocupará la misma masa de aire a 0 ºC y la presión a
emmainna [20.7K]

Answer:

El volumen que ocupará la misma masa de aire es 839.49 mL.

Explanation:

Las condiciones normales de presión y temperatura (abreviado CNPT) o presión y temperatura normales (abreviado PTN o TPN), son términos que implican que la temperatura referenciada es de 0ºC (273,15 K) y la presión de 1 atm (definida como 101.325 Pa).

La ley de Boyle dice que “El volumen ocupado por una determinada masa gaseosa a temperatura constante, es inversamente proporcional a la presión”  y se matemáticamente como

Presión*Volumen=constante

o P*V=k

La ley de Charles es una ley que dice que cuando la cantidad de gas y de presión se mantienen constantes, el cociente que existe entre el volumen y la temperatura siempre tendrán el mismo valor:  

\frac{V}{T} =k

La ley de Gay-Lussac​ establece que la presión de un volumen fijo de un gas, es directamente proporcional a su temperatura. Se expresa matemáticamente como:

\frac{P}{T} =k

Combinando estas tres leyes se obtiene:

\frac{P*V}{T} =k

Siendo un estado inicial 1 y un estado final 2, la expresión anterior queda determinada como:

\frac{P1*V1}{T1} =\frac{P2*V2}{T2}

En este caso:

  • P1=  101325 Pa
  • V1= 773 mL
  • T1= 273.15 K
  • P2= 93,3 kPa= 93300 Pa
  • V2= ?
  • T2= 0°C= 273.15 K

Reemplazando:

\frac{101325 Pa*773 mL}{273,15 K} =\frac{93300 Pa*V2}{273.15 K}

y resolviendo obtenes:

V2=\frac{273.15 K}{93300 Pa} *\frac{101325 Pa*773 mL}{273,15 K}

V2= 839,49 mL

<u><em>El volumen que ocupará la misma masa de aire es 839.49 mL.</em></u>

8 0
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TRUE or FALSE. The particles of a gas are packed closely together and don't have as much movement as the particles of a solid or
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