It's likely what's wanted is
<span><span>Li</span>→<span><span>Li</span><span>2+</span></span>+2<span>e−
</span></span>
The reason is because IEs are usually reported from the neutral atom, that is, IE2 is the energy required to remove two electrons from a neutral Li atom, as above, rather than the additional energy required to remove one more electron from an Li+ cation.
Answer: solvent
solvent is A solvent is usually a liquid
The correct answer is 1000 Kg/M³
Density of water =1-g/cm3.
We know 1- g= 10^-³ Kg
cm³ =(10^-2)³= 10^-6
Substituting we get
Density of water
= 1 x (1x10^-³)/10^-6 Kg/M³
= 1x10^3 = 1000 Kg/M³
<h3>
what is density?</h3>
Density is the mass of a material substance per unit volume. Density is defined as d = M/V, where d represents density, M is mass, and V is volume. Density is generally measured in grammes per cubic centimetre. Water, for example, has a density of 1 gramme per cubic centimetre, but Earth has a density of 5.51 grammes per cubic centimetre. Density is sometimes measured in kilos per cubic metre (in metre-kilogram-second or SI units). The density of air, for example, is 1.2 kilogrammes per cubic metre. Textbooks and handbooks list the densities of common solids, liquids, and gases.
learn more about density refer:
brainly.com/question/17780219
#SPJ4
The key to solving this problem is density. Density determines the mass of a molecule for a certain volume. Kia is given a beaker containing 100 g which volume is at <span>100 mL mark. Then the density of the liquid would be:
</span>density=mass/volume
density= 100g/ 100ml= 1g/ml
If t<span>he water now comes up to the 50 mL mark, then the weight would be:
</span>density = mass/volume
mass = volume * density
<span>mass = 50ml * (1g/ml)= 50g</span>
2H2 + O2 -> 2H20 is the balanced equation for the reaction of Hydrogen with Oxygen to form water so If you have 32g of O2 this is a simple Dimensional analysis problem 32g O2 x 36.03056g H20/31.9988g O2 this way the O2 cancels out and you are left with just the H2O so your raw answer would be 36.0319112, then if your instructor requires a significant figure answer that would be to 2 significant figures the information you were given 32g O2, so as above 36g or Water are produced. Just a different way to view and solve the problem with the balanced equation so you can see the way everything relates to everything else. the molar masses of O2 and H2O are simply found my adding up 2 Oxygens 15.9994g x2 = 31.9988g and H2O = 2(1.00794) + 15.9994 = 18.01258 but you then have to multiply that by 2 because the reaction states you get 2 mols in the reaction so that is where I came up with the 36.03056g for the solution. Hope this helps. Dimensional Analysis is and can be one of the best ways to solve these problems, because not always are you going to be dealing with 1:2 ratios.
