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Slav-nsk [51]
3 years ago
8

What is the average distance between oxygen molecules at stp?

Chemistry
1 answer:
ValentinkaMS [17]3 years ago
6 0

Although all gases closely follow the ideal gas law PV = nRT under appropriate conditions, each gas is also a unique chemical substance consisting of molecular units that have definite masses. In this lesson we will see how these molecular masses affect the properties of gases that conform to the ideal gas law.

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La configuración electrónica mas probable para el anión J -1 del elemento J con Z = 17 es:
Elanso [62]

Answer:

Explanation:

6 0
3 years ago
Which two solutions, when mixed together, will undergo a double replacement reaction and form a white, solid substance
Scrat [10]

Which two solutions, when mixed together, will undergo a double replacement reaction and form a white, solid substance?


1. NaCl(aq) and LiNO3(aq)

2. KCl(aq) and AgNO3(aq)  answer

3. KCl(aq) and LiCL(aq)

4. NaNO3(aq) and AgNO3(aq)


2 is the answer because AgCl is formed and that is a white ppt.

5 0
3 years ago
Read 2 more answers
Each step in the following process has a yield of 70.0%. CH4+4Cl2⟶CCl4+4HCl CCl4+2HF⟶CCl2F2+2HCl The CCl4 formed in the first st
Nadusha1986 [10]

Answer:

n(HCl)=1.96 mol

Explanation:

CH4+4Cl2⟶CCl4+4HCl

CCl4+2HF⟶CCl2F2+2HCl

With ideal yields we will end up with 4 moles of HCl.

With 70% yields on every stage

n(HCl)=0.7*0.7*4=1.96 mol

8 0
3 years ago
Tarnish on copper is the compound CuO. A tarnished copper plate is placed in an aluminum pan of boiling water. When enough salt
oksian1 [2.3K]

Answer:

The standard cell potential is 2.00 V

Explanation:

<u>Step 1:</u> Data given

Cu is cathode because of higher EP

Al3++3e−→Al       E∘=−1.66 V     anode

Cu2++2e−→Cu    E∘=0.340 V    cathode

<u>Step 2:</u> Balance both equations

2*(Al → Al3+-3e−)       E∘=1.66 V    

3*(Cu2++2e−→Cu)    E∘=0.340 V

<u>Step 3:</u> The netto equation

2 Al + 3Cu2+ +6e- → 2Al3+ + 3Cu -6e-

2 Al + 3Cu2+  → 2Al3+ + 3Cu

<u>Step 4:</u> Calculate the standard cell potential

E∘cell = E∘cathode - E∘anode

E∘cell = E∘ Cu2+/Cu - E∘ Al3+/Al

E∘cell =0.340 V - (-1.66) = 2.00 V

The standard cell potential is 2.00 V

4 0
3 years ago
Calculate the volume of an object that has a density of 4 g/mL and has a mass of 128 grams. Show your work
SOVA2 [1]
The first one is 32mL and the second one is 2.62 and I think it’s grams/mL I’m not for sure about the letters on the second one

4 0
2 years ago
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