This is not an redox reaction because the oxidation number of Oxygen atom is not changing.
AgNO3 ( aq ) + NaI ( aq ) = NaNO3 ( aq ) + AgI ( s ) .
Answer:
i. n = 5
ii. ΔE = 7.61 ×
KJ/mole
Explanation:
1. ΔE = (1/λ) = -2.178 ×
(
-
)
(1/434 ×
) = -2.178 ×
(
)
⇒ 434 ×
= (1/-2.178 ×
)![\frac{n^{2}_{final} *n^{2}_{initial} }{n^{2}_{initial} - n^{2}_{final} }](https://tex.z-dn.net/?f=%5Cfrac%7Bn%5E%7B2%7D_%7Bfinal%7D%20%2An%5E%7B2%7D_%7Binitial%7D%20%20%20%7D%7Bn%5E%7B2%7D_%7Binitial%7D%20-%20n%5E%7B2%7D_%7Bfinal%7D%20%20%20%20%7D)
But,
= 2
434 ×
= (1/2.178 ×
)![\frac{2^{2} n^{2}_{initial} }{n^{2}_{initial} - 2^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B2%5E%7B2%7D%20n%5E%7B2%7D_%7Binitial%7D%20%20%7D%7Bn%5E%7B2%7D_%7Binitial%7D%20-%202%5E%7B2%7D%20%20%7D)
434 ×
× 2.178 ×
= ![(\frac{4n^{2}_{initial} }{n^{2}_{initial} - 4 })](https://tex.z-dn.net/?f=%28%5Cfrac%7B4n%5E%7B2%7D_%7Binitial%7D%20%20%7D%7Bn%5E%7B2%7D_%7Binitial%7D%20-%204%20%7D%29)
⇒
= 5
Therefore, the initial energy level where transition occurred is from 5.
2. ΔE = hf
= (hc) ÷ λ
= (6.626 × 10−34 × 3.0 ×
) ÷ (434 ×
)
= (1.9878 ×
) ÷ (434 ×
)
= 4.58 ×
J
= 4.58 ×
KJ
But 1 mole = 6.02×
, then;
energy in KJ/mole = (4.58 ×
KJ) ÷ (6.02×
)
= 7.61 ×
KJ/mole
Answer:
1:2:1
Explanation:
i just think hai .its just a guess from my side...sorry if i m wrong...