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Zigmanuir [339]
3 years ago
13

This is due at 2:00 am today. I only have a few points. No links please I need a real answer.

Chemistry
1 answer:
GuDViN [60]3 years ago
5 0

Answer:

7.5 g of AlCl3

Explanation:

The given equation is;

NaOH + AlCl3 --> Al(OH)3 + NaCI.

By inspection, it is not balanced because OH and Clare not equal on both sides of the equation.

Thus, let's make them equal by balancing the equation.

Cl has 3 on the left, so we will make it to have 3 on the right. Same thing with OH on the right and we will make it to have 3 on the left. Thus:

3NaOH + AlCl3 --> Al(OH)3 + 3NaCI

We can see that;

NaOH has 3 moles

While AlCl3 has 1 mole

Thus, to find how many grams of AlCl3 will be required to completely react with 2.25g of NaOH ;

2.25g of NaOH × (3 moles NaOH/39.997 g/mol of NaOH) × (1 mole of AlCl3/3 moles of NaOH) × (133.34 g/mol of AlCl3/1 mol AlCl3) = 7.5 g of AlCl3

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Answer:

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nika2105 [10]
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3 years ago
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Maurinko [17]
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Marrrta [24]

Answer:

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8 0
3 years ago
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Answer:

C_t=0.165M

Explanation:

From the question we are told that:

Slope K=0.056 M-1 s -1

initial Concentration C_1=2.2M

Time t=100

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\frac{1}{C}_t=kt+\frac{1}{C}_0

\frac{1}{C}_t=0.056*100+\frac{1}{2.2}_0

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4 0
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