3 years ago

Viết các đồng phân cấu tạo mạch hở của C4H6O2 cùng nhóm chức axit

Chemistry

1 answer:

Aleksandr-060686 [28]3 years ago

8 0

Answer:

+ axit

CH2=CH-CH2-COOH,

CH3-CH=CH-COOH (tính cả đồng phân hình học)

CH2=C(CH3)-COOH.

+ este

HCOOCH=CH-CH3 (tính cả đồng phân hình học)

HCOO-CH2-CH=CH2,

HCOOC(CH3)=CH2.

CH3COOCH=CH2

CH2=CH-COOCH3

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