I think the answer is a or d
Answer:
A. Along warm-water currents from warmer regions to colder regions
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Explanation:
<u>Solution and Explanation:</u>
[La3+] = 0.1 M
<u>At the equilibrium:
</u>
La(IO3)3 <----> La3+ + 3 IO3-
0.1 +s 3s
![\mathrm{Ksp}=[\mathrm{La} 3+][\mathrm{IO} 3-]^{\wedge} 3](https://tex.z-dn.net/?f=%5Cmathrm%7BKsp%7D%3D%5B%5Cmathrm%7BLa%7D%203%2B%5D%5B%5Cmathrm%7BIO%7D%203-%5D%5E%7B%5Cwedge%7D%203)
![7.5 * 10^{\wedge}-12=(0.1+s) *(3 s)^{\wedge} 3](https://tex.z-dn.net/?f=7.5%20%2A%2010%5E%7B%5Cwedge%7D-12%3D%280.1%2Bs%29%20%2A%283%20s%29%5E%7B%5Cwedge%7D%203)
Since Ksp is small, s can be ignored as compared to the 0.1
The above shown expression thus becomes:
![7.5 * 10 \wedge-12=(0.1) *(3 s) \wedge 3](https://tex.z-dn.net/?f=7.5%20%2A%2010%20%5Cwedge-12%3D%280.1%29%20%2A%283%20s%29%20%5Cwedge%203)
![7.5 * 10^{\wedge}-12=0.1 * 27(\mathrm{s})^{\wedge} 3](https://tex.z-dn.net/?f=7.5%20%2A%2010%5E%7B%5Cwedge%7D-12%3D0.1%20%2A%2027%28%5Cmathrm%7Bs%7D%29%5E%7B%5Cwedge%7D%203)
![s=1.406 * 10^{\wedge}-4 \mathrm{M}](https://tex.z-dn.net/?f=s%3D1.406%20%2A%2010%5E%7B%5Cwedge%7D-4%20%5Cmathrm%7BM%7D)
<u>Answer: 1.4*10^-4 M
</u>