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kirill115 [55]
3 years ago
7

Viết các đồng phân cấu tạo mạch hở của C4H6O2 cùng nhóm chức axit

Chemistry
1 answer:
Aleksandr-060686 [28]3 years ago
8 0

Answer:

+ axit

CH2=CH-CH2-COOH,

CH3-CH=CH-COOH (tính cả đồng phân hình học)

CH2=C(CH3)-COOH.

+ este

HCOOCH=CH-CH3 (tính cả đồng phân hình học)

HCOO-CH2-CH=CH2,

HCOOC(CH3)=CH2.

CH3COOCH=CH2

CH2=CH-COOCH3

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pav-90 [236]

Answer:

(A) The value of Kc for this reaction increases as temperature increases, because the reaction is endothermic.

Step-by-step explanation:

   N₂O₄      ⇌       2NO₂

colourless      reddish-brown

NO₂ is a reddish-brown gas, while N₂O₄ is colourless.

When you cooled the sample to 0 °C, the position of equilibrium shifted to form more N₂O₄, that is, it <em>shifted to the left</em>.

According to <em>Le Châtelier's Principle,</em> when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

You applied a stress: you removed heat from the system. It responded by shifting in the direction that produces more heat (<em>to the left</em>).

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Furthermore, since the position of equilibrium shifted in the direction of reactants, the equilibrium constant decreased.

The value of K <em>decreases as the temperature decreases</em>. If we say it the other way, the value of K increases as the temperature increases.

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7 0
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Given that it requires 27.9 ml of 0.270 m na2s2o3(aq) to titrate a 15.0-ml sample of i3–(aq), calculate the molarity of i3–(aq)
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<em>Step 2</em>. Calculate the <em>moles of S_2O_3^(2-)</em>

Moles of S_2O_3^(2-)

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<em>Step 3</em>. Calculate the <em>moles of I_3^(-) </em>

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