The answer to your question would be (a) because an orange has a pH of 3.3 to 4.9. Which is on the acid side of the scale.
80
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100
or
4
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5
if u want the simplest terms
Answer:
The change in T° is 47.1 °C
Explanation:
Calorimetry formula to solve this:
Q = m . C . ΔT
We replace the data gien:
635 J = 3.50×10⁻² kg . 0.385 J/g°C . ΔT
In units of C, we have g and the mass (m) is in kg. So let's convert it from kg to g → 3.50×10⁻² kg . 1000 g / 1kg = 35 g. Now we can determine the ΔT:
635 J = 35 g . 0.385 J/g°C . ΔT
635 J / 35 g . 0.385 J/g°C = ΔT
47.1°C = ΔT
Fahrenheit. 60 degrees celcius is 140 degrees fahrenheit, which is very hot.
