Answer: Hello,Mass ratio charge is.....................
Explanation: In mass spectroscopy, the mass-to-charge ratio (symbols: m/z, m/e) of a cation is equal to the mass of the cation divided by its charge. ... The mass of the molecular ion is equal to the molecular weight of the compound. Thus, the mass-to-charge ratio of the molecular ion is equal to the molecular weight of the compound.
One mole of a substance contains 6.02×10∧23 particles,
1 mole of a aluminium contains 27 g
35 g of aluminium contains 35/27 =1.296 moles
Thus, the number of particles will be 1.296 × 6.02 ×10∧23
= 7.804 × 10∧23 particles,
Hence, 35 g of Aluminium contains 7.804 × 10∧23 atoms
Answer:
diboron trioxide Formula: B 2 O 3 Molecular weight: 69.620 CAS Registry Number: 1303-86-2
Explanation:
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<u><em>hope that helps you</em></u>╰(*°▽°*)╯</h3>
Answer : The final concentration of
is, 2.9 M
Explanation :
Expression for rate law for first order kinetics is given by:
![t=\frac{2.303}{k}\log\frac{a}{a-x}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B2.303%7D%7Bk%7D%5Clog%5Cfrac%7Ba%7D%7Ba-x%7D)
where,
k = rate constant = ![5.89\times 10^{-3}\text{ min}^{-1}](https://tex.z-dn.net/?f=5.89%5Ctimes%2010%5E%7B-3%7D%5Ctext%7B%20min%7D%5E%7B-1%7D)
t = time passed by the sample = 3.5 min
a = initial concentration of the reactant = 3.0 M
a - x = concentration left after decay process = ?
Now put all the given values in above equation, we get
![3.5=\frac{2.303}{5.89\times 10^{-3}}\log\frac{3.0}{a-x}](https://tex.z-dn.net/?f=3.5%3D%5Cfrac%7B2.303%7D%7B5.89%5Ctimes%2010%5E%7B-3%7D%7D%5Clog%5Cfrac%7B3.0%7D%7Ba-x%7D)
![a-x=2.9M](https://tex.z-dn.net/?f=a-x%3D2.9M)
Thus, the final concentration of
is, 2.9 M