Answer:
Stainless steel
Explanation:
Hope I answered your question.
Answer:
Between 5 & 10 MPa in Table B.1.4
Explanation:
150F = 65°C
State 1:
T = 65°C , x = 0.0; Table B.1.1: v = 0,001020 m^3
/kg
Process: T = constant = 65°C
State 2:
T, v = 0.99 x v
f (65°C) = 0.99 x 0,001020 = 0.0010098 m^3
/kg
Between 5 & 10 MPa in Table B.1.4
Answer:
The power required to cool the water is 1.11Kw.
Hence the correct option is (b).
Explanation:
Power needed to cool down is equal to heat extract from the water.
Given:
Volume of water is 1 liter.
Initial temperature is 100C.
Final temperature is 20C.
Time is 5 minutes.
Take density of water as 100 kg/m3.
Specific heat of water is 4.186 kj/kgK.
Calculation:
Step1
Mass of the water is calculated as follows:


m=1kg
Step2
Amount of heat extraction is calculated as follows:


Q=334880 j.
Step3
Power to cool the water is calculated as follows:


P=1116.26W
or

P=1.11 Kw.
Thus, the power required to cool the water is 1.11Kw.
Hence the correct option is (b).
Answer: Incoherent question
Explanation: This is an act of plagiarism at subjecting the tutor to unnecessary stress at answering the purported question.