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svlad2 [7]
2 years ago
7

A laminated steel ring is wound with 3000 turns. When the magnetism current varies between 7 and 9 A, the magnetic flux varies b

etween 860 and 900Nwb, calculate the incremental inductance of the coil over this range of current variation
Engineering
1 answer:
Klio2033 [76]2 years ago
4 0

Answer:

60000 H

Explanation:

We are given;

Number of turns; N = 3000 turns

Change in flux = 900 - 860 = 40 Wb

Change in current = 9 - 7 = 2 A

Now, the formula for incremental inductance is given as:

L = N(Change in flux/Change in current) where;

N is Number of turns

Plugging in the relevant values, we have;

L = 3000(40/2)

L = 60000 H.

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goldenfox [79]

Answer:

using System;

using System.Collections.Generic;

using System.Linq;

public class Problem1 {

public static IEnumerable < int > myFilter(IEnumerable < int > input) {

return input.Where((val, index) => {

//First remove all multiples of 6 less than 42

return !(val % 6 == 0 && val < 42);

}).Select((val, index) => {

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});

}

public static void Main(string[] args) {

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var listForProblem = Enumerable.Range(1, 100).Select(i => rnd.Next() % 101);

var answer = Problem1.myFilter(listForProblem);

foreach(int i in answer) {

Console.WriteLine(i);

}

}

}

Explanation:

The Problem 1 solution is explanatory enough.

Your problem 2 question is lacking details. However, i have written a code that sorts it.

6 0
3 years ago
In a voltage-divider biased pnp transistor, there is no base current, but the base voltage is approximately correct. The most li
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Answer:

The coattail effect

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