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svlad2 [7]
3 years ago
7

A laminated steel ring is wound with 3000 turns. When the magnetism current varies between 7 and 9 A, the magnetic flux varies b

etween 860 and 900Nwb, calculate the incremental inductance of the coil over this range of current variation
Engineering
1 answer:
Klio2033 [76]3 years ago
4 0

Answer:

60000 H

Explanation:

We are given;

Number of turns; N = 3000 turns

Change in flux = 900 - 860 = 40 Wb

Change in current = 9 - 7 = 2 A

Now, the formula for incremental inductance is given as:

L = N(Change in flux/Change in current) where;

N is Number of turns

Plugging in the relevant values, we have;

L = 3000(40/2)

L = 60000 H.

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Saturated liquid water at 150 F is put under pressure to decrease the volume by 1% while keeping the temperature constant. To wh
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Between 5 & 10 MPa in Table B.1.4

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4 years ago
How much power would you need to cool down a closed, 1 Liter container of water from 100°C to 20°C in 5 minutes? (a) 1.1W (b)1.1
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Answer:

The power required to cool the water is 1.11Kw.

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Power needed to cool down is equal to heat extract from the water.

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Volume of water is 1 liter.

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Final temperature is 20C.

Time is 5 minutes.

Take density of water as 100 kg/m3.

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Step1

Mass of the water is calculated as follows:

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m=1kg

Step2

Amount of heat extraction is calculated as follows:

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Step3

Power to cool the water is calculated as follows:

P=\frac{Q}{t}

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4 years ago
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