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svlad2 [7]
3 years ago
7

A laminated steel ring is wound with 3000 turns. When the magnetism current varies between 7 and 9 A, the magnetic flux varies b

etween 860 and 900Nwb, calculate the incremental inductance of the coil over this range of current variation
Engineering
1 answer:
Klio2033 [76]3 years ago
4 0

Answer:

60000 H

Explanation:

We are given;

Number of turns; N = 3000 turns

Change in flux = 900 - 860 = 40 Wb

Change in current = 9 - 7 = 2 A

Now, the formula for incremental inductance is given as:

L = N(Change in flux/Change in current) where;

N is Number of turns

Plugging in the relevant values, we have;

L = 3000(40/2)

L = 60000 H.

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