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inn [45]
3 years ago
5

Blood pressure is conventionally measured in the dimensions of millimeters in a column of mercury, and the readings are expresse

d as two numbers, for example, 120 and 80. The first number is called the systolic value, and it is the maximum pressure developed as the heart contracts. The second number (called the diastolic reading) is the pressure when the heart is at rest. In the units of kPa and psi, what is the difference in pressure between the given systolic and diastolic readings? The density of mercury is 13.54 Mg/m3.
Engineering
1 answer:
belka [17]3 years ago
6 0

Answer:

- the difference in pressure between the given systolic and diastolic readings in KPa is 5.313 KPa

- the difference in pressure between the given systolic and diastolic readings in psi is 0.77 psi

Explanation:

Given the data in the question;

blood pressure reading = 120 and 80 { systolic and diastolic }

To determine the difference in pressure between the two readings, we use the equation as follows;

change in pressure ΔP = p × g × h

where p is mercury density, g is acceleration due to gravity and h is difference of height in mercury column.

Frist,  

difference of height in mercury column h = 120 - 80 = 40 mm = 0.04 m

given that; The density of mercury is 13.54 Mg/m³ = 13.54 × 10³ kg/m³

Not that Mg is Megagrams not Milligrams }

we know that g = 9.81 m/s²

so we substitute into our equation;

change in pressure ΔP = (13.54 × 10³) × 9.81 × 0.04

ΔP = 5313.096 kg/m-s² ≈ 5313.096 N/m²

ΔP = 5.313 KPa

Therefore, the difference in pressure between the given systolic and diastolic readings in KPa is 5.313 KPa.

In psi,

ΔP = 5.313 KPa

ΔP = 5313 Pa

ΔP = 5313 pa × ( 1.45 × 10⁻⁴ psi / 1 Pa )

ΔP = 0.770385 psi ≈ 0.77 psi

Therefore, the difference in pressure between the given systolic and diastolic readings in psi is 0.77 psi

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A seamless pipe 800mm diameter contains a fluid under a pressure of 2N/mm2. If the permissible tensile stress is 100N/mm2, find
Bad White [126]

Answer:

8 mm

Explanation:

Given:

Diameter, D = 800 mm

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Permissible tensile stress, σ = 100 N/mm²

Now,

for the pipes, we have the relation as:

\sigma=\frac{\textup{PD}}{\textup{2t}}

where, t is the thickness

on substituting the respective values, we get

100=\frac{\textup{2\times800}}{\textup{2t}}

or

t = 8 mm

Hence, the minimum thickness of pipe is 8 mm

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3 years ago
Your family has asked you to estimate the operating costs of your clothes dryer for the year. The clothes dryer in your home has
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Answer:

The costs to run the dryer for one year are $ 9.03.

Explanation:

Given that the clothes dryer in my home has a power rating of 2250 Watts, and to dry one typical load of clothes the dryer will run for approximately 45 minutes, and in Ontario, the cost of electricity is $ 0.11 / kWh, to calculate the costs to run the dryer for one year the following calculation must be performed:

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2250/45 = 50 watts per minute

45 x 365 = 16,425 / 60 = 273.75 hours of consumption

50 x 60 = 300 watt = 0.3 kw / h

0.3 x 273.75 = 82.125

82.125 x 0.11 = 9.03

Therefore, the costs to run the dryer for one year are $ 9.03.

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A long, circular aluminum rod is attached at one end to a heated wall and transfers heat by convection to a cold fluid.
Trava [24]

Answer:

a. Heat removal rate will increase

b. Heat removal rate will decrease

Explanation:

Given that

One end of rod is connected to the furnace and rod is long.So this rod can be treated as infinite long fin.

We know that heat transfer in fin given as follows

Q_{fin}=\sqrt{hPKA}\ \Delta T

We know that area

A=\dfrac{\pi}{4}d^2

Now when diameter will triples then :

A_f=\dfrac{\pi}{4}{\left (3d \right )}^2

A_f=9A

Q'_{fin}=\sqrt{9hPKA}\ \Delta T

Q'_{fin}=3\sqrt{hPKA}\ \Delta T

Q'_{fin}=3Q

So the new heat transfer will increase by 3 times.

Now when copper rod will replace by aluminium rod :

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3 years ago
A student checks her car's tyre air pressure at a petrol station and finds it is 31 psi. Re-express this as an absolute pressure
victus00 [196]

Answer:

Absolute Pressure=315.06256 kPa

Explanation:

Gauge pressure= 31 psi

Atmospheric Pressure at Sea level= 1 atm=101.325 kPa

1\ psi=6.89476\ kPa\\\Rightarrow 31\ psi=31\times 6.89476\\\Rightarrow 31\ psi=213.73756\ kPa=Gauge\ Pressure\\Absolute\ Pressure=Gauge\ Pressure+Atmospheric\ Pressure\\\Rightarrow Absolute\ Pressure=213.73756+101.325\\\therefore Absolute\ Pressure=315.06256\ kPa

5 0
3 years ago
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