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3 years ago

8

Today, there are ____ GMO crops currently produced in the US.

2 answers:

babymother [125]3 years ago

8 0

Answer: I think that is 55

Explanation: I hope I help

kondor19780726 [428]3 years ago

6 0

The answer is c. Have a good day/night.

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Help me with this question please

sveticcg [70]

Answer:it loses one electron

Explanation:

When it loses one electron it has a noble gas configuration

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4 years ago

All magnetic minerals will have the element iron in the chemical composition true or false

Margaret [11]

The statement is true. If a mineral lacks the presence of iron in it then it will be generally dimagnetic. It means non iron minerals do not show magnetic property in general. There are some minerals like serpentine do show some magnetic susceptibility, however this is negligible as compared to iron minerals hence the ores with no magnetic are generally diamagnetic.

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3 years ago

How do two nonmetal atoms become more stable and form

kvv77 [185]

It’s A hope this helps

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3 years ago

Three gases (8.00 g of methane, CH4, 18.0 g of ethane, C2H6, and an unknown amount of propane, C3H8) were added to the same 10.0

klemol [59]

Answer:

Partial pressure of methane: 1.18 atm

Partial pressure of ethane: 1.45 atm

Partial pressure of propane: 2.35 atm

Explanation:

Let the total moles of gases in a container be n.

Total pressure of the gases in a container =P = 5.0 atm

Temperature of the gases in a container =T = 23°C = 296.15 K

Volume of the container = V = 10.0 L

$PV=nRT$ (Ideal gas equation)

$n=\frac{PV}{RT}=\frac{5.0 atm\times 10.0 L}{0.0821 atm L/mol K\times 296.15 K}=2.0564 mol$

Moles of methane gas = $n_1=\frac{8.00 g}{16.04 g/mol}=0.4878 mol$

Moles of ethane gas = $n_2=\frac{18.00 g}{30.07 g/mol}=0.5986 mol$

Moles of propane gas = $n_3=?$

$n=n_1+n_2+n_3$

$n_3=n-n_1-n_2=2.0564 mol-0.4878 mol-0.5986 mol= 0.9700 mol$

Partial pressure of all the gases can be calculated by using Raoult's law:

$p_i=P\times \chi_i$

$p_i$ = partial pressure of 'i' component.

$\chi_1$ = mole fraction of 'i' component in mixture

P = total pressure of the mixture

Partial pressure of methane:

$p_1=P\times \chi_1=P\times \frac{n_1}{n_1+n+2+n_3}=P\times \frac{n_1}{n}$

$p_1=5.00 atm\times \frac{0.4878 mol}{2.0564 mol}=1.18 atm$

Partial pressure of ethane:

$p_2=P\times \chi_2=P\times \frac{n_2}{n_1+n+2+n_3}=P\times \frac{n_2}{n}$

$p_2=5.00 atm\times \frac{0.5986 mol}{2.0564 mol}=1.45 atm$

Partial pressure of propane:

$p_3=P\times \chi_3=P\times \frac{n_3}{n_1+n+2+n_3}=P\times \frac{n_3}{n}$

$p_3=5.00 atm\times \frac{0.9700 mol}{2.0564 mol}=2.35 atm$

5 0

4 years ago

Give an example of biotic living conditions.

Brrunno [24]

Answer:

plants and animals

Explanation:

3 0

3 years ago

Read 2 more answers