Using electronegative. If the difference is between 0 and .4, the bond is nonpolar,If the difference is between .4 and about 1.9, the bond is polar, and if the difference is over 1.9 it is typically ionic.
Answer:
Explanation:
This is a skeleton problem because the reacting species are not given. We do not have any information about the metal and non-metal reacting. Let us give a run down on how to solve this kind of problem. I hope you find it useful.
Firstly, establish the reaction equation. This will contain the reactants and products. The equation must be balanced in order to comply with the law of conservation of matter.
Secondly, solve from the known to the unknown specie. The known is the one which we can accurately determine the number of moles from. Using the number of moles of the known, we can find the moles of the unknown.
To find the number of moles;
Number of moles = 
molar mass is the sum of the atomic masses of the given compound whose mass we know.
mass = 5g
Thirdly; compared the number of moles of the known to the unknown using relationships and ratios between the two of them. F
For example, if :
2 mole of known gives 1 moles of unknown
solved mole of the known will give
moles of unknown
Lastly:
Now use this mole to find the mass of the unknown;
Mass of unknown = number of moles of unknown x molar mass
Answer:
Empirical formula
C3H2Cl
Molecular formula
C6H4Cl2
Explanation:
Firstly, we can get the mass of carbon and hydrogen produced by calculating their number of moles from that of carbon iv oxide and water respectively.
To get the number of moles of carbon iv oxide, we simply make a division. The number of moles is the mass of carbon iv oxide divided by the molar mass of carbon iv oxide. The molar mass of carbon iv oxide is 44g/mol. The number of moles is thus 3.02/44 = 0.069
One atom of carbon is present in Carbon iv oxide. This means 0.069 moles of carbon is present. The mass of carbon present equals the atomic mass of carbon multiplied by the number of moles = 0.069 * 12 = 0.83g
The mass of water is 0.412g, the number of moles is 0.412/18 = 0.023
In water, there are two atoms of hydrogen. Hence the number of moles of hydrogen is 2 * 0.023 = 0.046
The mass of hydrogen is the number of moles of hydrogen multiplied by the atomic mass unit of hydrogen = 0.046 * 1 = 0.046g
Now we need to know the mass of chlorine. We simply subtract the masses of hydrogen and carbon.
1.68-0.046-0.83 = 0.804
Now we proceed to calculate the empirical formula. We simply divide the mass of each by their atomic masses and then proceed from there.
H = 0.046/1 = 0.046
C = 0.83/12 = 0.069
Cl = 0.804/35.5 = 0.023
We divide by the smallest number which is that of that of carbon
H = 0.046/0.023= 2
C = 0.069/0.023= 3
Cl = 0.023/0.023 = 1
The empirical formula would thus be C3H2Cl
The molecular formula can be calculated using the molar mass;
(C3H2Cl)n = 147
(36+ 2 + 35.5 ) = 147
73.5n = 147
n = 147/73.5 = 2
The molecular formula is thus C6H4Cl2