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3 years ago

How many parts per million of fluoride in a solution that is 500 grams of fluoride and 500,000 liters water

Chemistry

1 answer:

erik [133]3 years ago

7 0

0.000001‬ppm

Explanation:

Mass of fluoride = 500g

Volume of water = 500000liters

Unknown:

Parts per million of fluoride = ?

Solution:

The parts per million is the amount of solute in milligram dissolved in a liter of water or milligram per kilogram of solvent

It is a unit used to express very small concentration.

we need to convert g - mg

500g = 500 x 10⁻³mg = 0.5mg

Concentration in parts per million = $\frac{mass in mg}{Volume in liters}$

Concentration in parts per million = $\frac{0.5}{500000}$ = 0.000001‬ppm

learn more:

Parts per million brainly.com/question/2854033

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An electron that is in the highest energy level of an atom and determines the atom's chemical properties is called a(n)

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3 years ago

Sulfuric acid dissolves aluminum metal according to the following reaction:

Fiesta28 [93]

Answer:

$m_{H_2SO_4}=81.7gH_2SO_4$

$m_{H_2}=1.67gH_2$

Explanation:

Hello,

Based on the given undergoing chemical reaction is is rewritten below:

$2Al (s) + 3H_2SO_4 (aq)\rightarrow Al _2(SO4)_3 (aq) + 3H_2 (g)$

By stoichiometry we find the minimum mass of H2SO4 (in g) as shown below:

$m_{H_2SO_4}=15.0gAl*\frac{1molAl}{27gAl}*\frac{3molH_2SO_4}{2molAl}*\frac{98gH_2SO_4}{1molH_2SO_4} \\m_{H_2SO_4}=81.7gH_2SO_4$

Moreover, mass of H2 gas (in g) would be produced by the complete reaction of the aluminum block turns out:

$m_{H_2}=15.0gAl*\frac{1molAl}{27gAl}*\frac{3molH_2}{2molAl}*\frac{2gH_2}{1molH_2} \\m_{H_2}=1.67gH_2$

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3 0

3 years ago

Calculate the molarity 20ml of 3.5 m kci in to a final volume of 100 ml

satela [25.4K]

Answer:

Molarity = 0.7 M

Explanation:

Given data:

Volume of KCl = 20 mL ( 0.02 L)

Molarity = 3.5 M

Final volume = 100 mL (0.1 L)

Molarity in 100 mL = ?

Solution:

Molarity = number of moles of solute / volume in litter.

First of all we will determine the number of moles of KCl available.

Number of moles = molarity × volume in litter

Number of moles = 3.5 M × 0.02 L

Number of moles = 0.07 mol

Molarity in 100 mL.

Molarity = number of moles / volume in litter

Molarity = 0.07 mol /0.1 L

Molarity = 0.7 M

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3 years ago

Energy from the sun is transferred to the earth by:

pickupchik [31]

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3 years ago

How many moles of nitrogen gas are there in 16.8 L of this gas at STP?

sweet-ann [11.9K]

According to Avogadro's Law, same volume of any gas at standard temperature and pressure will occupy same volume. And one mole of any Ideal gas occupies 22.4 dm³ (1 dm³ = 1 L).

Data Given:

n = moles = ?
V = Volume = 16.8 L

Solution:
As 22.4 L volume is occupied by one mole of gas then the 16.8 L of this gas will contain....

= ( 1 mole × 16.8 L) ÷ 22.4 L

= 0.75 moles

Result:
16.8 L of Nitrogen gas will contain 0.75 moles at standard temperature and pressure.

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3 years ago