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WINSTONCH [101]
4 years ago
15

How many parts per million of fluoride in a solution that is 500 grams of fluoride and 500,000 liters water

Chemistry
1 answer:
erik [133]4 years ago
7 0

0.000001‬ppm

Explanation:

Mass of fluoride = 500g

Volume of water = 500000liters

Unknown:

Parts per million of fluoride = ?

Solution:

The parts per million is the amount of solute in milligram dissolved in a liter of water or milligram per kilogram of solvent

It is a unit used to express very small concentration.

 we need to convert g - mg

   500g = 500 x  10⁻³mg  = 0.5mg

   Concentration in parts per million = \frac{mass in mg}{Volume in liters}

Concentration in parts per million = \frac{0.5}{500000} = 0.000001‬ppm

learn more:

Parts per million brainly.com/question/2854033

#learnwithBrainly

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7 0
3 years ago
A scientist has 0.12 miles of a gas at a pressure of 4.06 kPa and a volume of 14 liters in an enclosed container. What is the te
natka813 [3]

Answer:

56972.17K

Explanation:

P = 4.06kPa = 4.06×10³Pa

V = 14L

n = 0.12 moles

R = 8.314J/Mol.K

T = ?

We need ideal gas equation to solve this question

From ideal gas equation,

PV = nRT

P = pressure of the ideal gas

V = volume the gas occupies

n = number of moles

R = ideal gas constant

T = temperature of the gas

PV = nRT

T = PV / nR

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T = 56840 / 0.99768

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3 years ago
Find the number of grams in 16.95 mol hydrogen peroxide (H2O2). Round your
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Answer: There are 576.46 number of grams present in 16.95 mol hydrogen peroxide (H_{2}O_{2}).

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Number of moles is defined as the mass of substance divided by its molar mass.

The molar mass of H_{2}O_{2} is 34.01 g/mol. Hence, mass of hydrogen peroxide present in 16.95 moles is calculated as follows.

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Thus, we can conclude that there are 576.46 number of grams present in 16.95 mol hydrogen peroxide (H_{2}O_{2}).

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3 years ago
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Answer:

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