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vovikov84 [41]
3 years ago
14

A jogger takes five minutes to run a distance of three kilometres. His speed, in metres per second, is approximately A) 5.5 M/S

B) 10 M/S C) 36 M/S D) 4.5 M/S
Physics
1 answer:
just olya [345]3 years ago
5 0

Answer:

His speed, in metres per second, is approximately 10m/s. The correct option is B.

Explanation:

Speed is defined as the rate in which an object cover a distance in a given time. It is measured in meters per second ( m/s). From the question, the jogger covered a distance of 3Km which when converted to meter is 3000meters in a given time 5 minutes which is 300seconds. The calculation of his speed in meter per second is shown below:

Distance= 3Km to meters ( as 1000meters = 1Km). Therefore 3× 1000 = 3000m

Time= 5 minutes to seconds ( as 1 minute = 60 Seconds). Therefore 5× 60= 300.

Speed= distance/ time

= 3000/300

= 10m/s

Therefore his speed, in metres per second, is approximately 10.

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According to the law of conservation of matter, which statement about chemical reactions is true?
satela [25.4K]

The correct answer is:

Atoms cannot be created or destroyed by chemical reactions.

4 0
3 years ago
Water flows at 0.850 m/s from a hot water heater, through a 450-kPa pressure regulator. The pressure in the pipe supplying an up
grin007 [14]

Answer:

The velocity is  v_2= 0.45 \ m/s

Explanation:

From the question we are told that

      The initial speed of the hot water is  v_1 = 0.85 \ m/s

     The pressure from the heater  P_1  =  450 \ KPa = 450 *10^{3} \ Pa

      The height of the hot water before flowing is  h_1 = 0 \ m

      The height of bathtub above the heater is h_2  =  3.70 \ m

       The pressure in the pipe is P_2 =  414 KPa = 414 *10^{3} \ Pa

       The density of water is \rho =  1000 \ kg/m^3

Apply Bernoulli equation

      P_1 + \rho gh_1 +\frac{1}{2} \rho v_1^2  =  \rho g h_2 + \frac{1}{2}\rho v_2 ^2

Substituting values

     (450 *10^{3}) + (1000 * 9.8 * 0) + (0.5 * 1000 * 0.85^2)  =  (1000 * *9.8*3.70) + (0.5*1000*v_2^2 )

=>   v_2^2 =  \frac{ (450 *10^{3}) + (1000 * 9.8 *0 ) + (0.5 * 1000 * 0.85^2) -[ (1000 * *9.8*3.70) ]}{0.5*1000}

=>   v_2= \sqrt{ \frac{ (450 *10^{3}) + (1000 * 9.8 * 0) + (0.5 * 1000 * 0.85^2) -[ (1000 * *9.8*3.70) ]}{0.5*1000}}

=>    v_2= 0.45 \ m/s

4 0
2 years ago
How much work is done lifting a 9.10-kg box straight up onto a shelf that is 1.80 m high
love history [14]

P= 10m = 10 x 9.10 = 91 N

Work is done lifting a 9.10-kg box straight up onto a shelf that is 1.80 m high :

A= Ph = 91 x 1.80 = 163.8 J

ok done. Thank to me :>

5 0
2 years ago
What are two ways in which you can increase the potential energy of a marble on a ramp?
valkas [14]

Answer:

As the marble starts rolling down the roller coaster, the amount of potential energy stored in the marble decreases while its kinetic energy increases. Potential energy is also converted into heat energy due to friction.

Explanation:

As the marble rolls down the hill its potential energy is converted to kinetic energy (its height decreases, but its velocity increases). When the marble goes back up the loop its height increases again and its velocity decreases, changing kinetic energy into potential energy.

8 0
3 years ago
You apply a net force on a soccer ball of 15 N. If the acceleration it has is 5 m/s2 what is the mass of the ball?​
Ipatiy [6.2K]

Answer:

<h2>3 kg </h2>

Explanation:

The mass of the ball can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

We have

m =  \frac{15}{5}  = 3 \\

We have the final answer as

<h3>3 kg</h3>

Hope this helps you

4 0
3 years ago
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