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vovikov84 [41]
3 years ago
14

A jogger takes five minutes to run a distance of three kilometres. His speed, in metres per second, is approximately A) 5.5 M/S

B) 10 M/S C) 36 M/S D) 4.5 M/S
Physics
1 answer:
just olya [345]3 years ago
5 0

Answer:

His speed, in metres per second, is approximately 10m/s. The correct option is B.

Explanation:

Speed is defined as the rate in which an object cover a distance in a given time. It is measured in meters per second ( m/s). From the question, the jogger covered a distance of 3Km which when converted to meter is 3000meters in a given time 5 minutes which is 300seconds. The calculation of his speed in meter per second is shown below:

Distance= 3Km to meters ( as 1000meters = 1Km). Therefore 3× 1000 = 3000m

Time= 5 minutes to seconds ( as 1 minute = 60 Seconds). Therefore 5× 60= 300.

Speed= distance/ time

= 3000/300

= 10m/s

Therefore his speed, in metres per second, is approximately 10.

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A battery of emf 5V and internal resistance 2ohm is joined to a resistor of 8ohm.Calculate the terminal potential difference. ​
nata0808 [166]

Answer:

4V

Explanation:

First, we calculate the total resistance to the given battery cell of emf 5V. The total resistance is the sum of all the resistance in the cell i.e.

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Using ohms law equation to calculate the current passing through the battery cell:

V = IR

Where; V = voltage, I = current, R = resistance

5V = I × 10Ω

I = 5/10

I = 0.5A

Terminal voltage is calculated by the us of the following equation:

V=emf−IR

Where; R is internal resistance

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3 0
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Part F A system experiences a change in internal energy of 14 kJkJ in a process that involves a transfer of 36 kJkJ of heat into
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Answer:

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Q = ΔE + W

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