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Mila [183]
3 years ago
13

Monochromatic light shines on the cathode in a photoelectric effect experiment, causing the emission of electrons. If the freque

ncy of the light stays the same but the intensity of the light shining on the cathode is increased:_________
a. The emitted electrons will be moving at a higher speed.
b. There will be more electrons emitted.
c. Neither A nor B are true.
d. Both A and B are true
Physics
1 answer:
professor190 [17]3 years ago
3 0

Answer:

<em>b. There will be more electrons emitted.</em>

Explanation:

In photoelectric emission, the energy of the emitted electron is dependent on the frequency of the wave incident on the plate; but not the intensity. The rate of electron emission per unit time however depends on the intensity of the incident light. So increasing the intensity of the light at constant frequency will only affect the number of electrons emitted per unit time.

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Explain why a ball thrown in space could keep moving forever, while a ball thrown here on Earth will come to a stop.
Dmitriy789 [7]

Answer:

In space there is no air resistance. on earth there is

in space there is no opposite forces acting on stopping the ball, so if you throw it it will go on forever.

on earth there is air resistance and gravity, this will pull the ball towards the ground and slow it down.

4 0
3 years ago
A gecko crawls vertically up and down a wall. Its motion is shown on the following graph of vertical position yyy vs. time ttt.
earnstyle [38]

Answer:

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4 0
3 years ago
An air-filled pipe is found to have successive harmonics at 945 Hz , 1215 Hz , and 1485 Hz . It is unknown whether harmonics bel
Aleonysh [2.5K]

Answer:

L = 0.635m

Explanation:

This problem involves the concept of stationary waves in pipes. For pipes closed at one end,

The frequency f = nv/4L for n = 1,3,5....n

For pipes open at both ends

f = nv/2L for n = 1,2,3,4...n

Assuming the pipe is closed at one end and that velocity of sound is 343m/s in air. If we are right we will obtain a whole number for n.

The film solution can be found in the attachment below.

8 0
3 years ago
When you push a child on a swing, your action is most effective when your pushes are timed to coincide with the natural frequenc
OleMash [197]

Answer:

T = 4.48 s

we can see that this time period is independent of the mass of the child so answer would be same if the child mass is different

Explanation:

Natural frequency of a simple pendulum of L length is given as

f = \frac{1}{2\pi}\sqrt{\frac{g}{L}}

so the time period of the oscillation is given as

T = 2\pi \sqrt{\frac{L}{g}}

so we will have

L = 5 m

T = 2\pi\sqrt{\frac{5}{9.81}}

T = 4.48 s

also from above formula we can see that this time period is independent of the mass of the child so answer would be same if the child mass is different

3 0
3 years ago
What is the displacement of the runner in 4 laps? *<br> 2 point
Serhud [2]

Answer:

There is no displacement.

Explanation:

Because the runner is running laps and returning to the original place, there is no displacement as displacement is relative to the change in location from the original position.

Hope this helps. . .

ly UwU

3 0
3 years ago
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