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AURORKA [14]
3 years ago
14

Can someone. help me solve this pls .

Mathematics
1 answer:
olchik [2.2K]3 years ago
7 0

Answer:

1.108

729 =  {n}^{6} \\  \sqrt[6]{729}  =   \sqrt[6]{ {n}^{6} }  \\ n = 1.108

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B
Radda [10]

Answer:

ΔCFE is a right triangle

ΔBEC is an acute triangle

ΔBFG is an equilateral triangle

ΔGAF is an obtuse isosceles triangle

5 0
3 years ago
Which number is the square root of 196
Elodia [21]
Hi there,

I think the answer is

14

Have a nice day
8 0
3 years ago
Solve the equation<br> 0.09w+1.8
ella [17]

Step-by-step explanation:

0.09w + 1.8 = 0

0.09w = 0 - 1.8

0.09w = - 1.8

0.09w ÷ 0.09 = - 1.8/ 0.09

w = - 20

7 0
2 years ago
Using the image above, if the density of the LEGO piece is 0.85 g/cm^3, what COULD be a possible measurement for the density of
grin007 [14]

The Lego is submerged under the oil and therefore, is more dense than the oil

The possible density of the oil is the option;

<u>0.79 g/cm³</u>

Reason:

Given:

The density of Lego = 0.85 g/cm³

Density of oil = Required

Solution:

The density of an object is the mass per unit volume it occupies

  • Density = \dfrac{Mass}{Volume}

Increase in density increases the mass a unit volume occupies, therefore, a

more dense object is heavier than a less dense object such that the less

dense object will float on a dense object

The oil is floating on the Lego, therefore, the Lego is more dense than the

oil, and we have;

  • Density of Lego > Density of oil

The density of Lego = 0.85 g/cm³

Therefore;

0.85 g/cm³ > Density of oil

From the given options, the option that has a density less than 0.85 g/cm³ is the the option 0.79 g/cm³

Therefore, the possible density of the oil is <u>0.79 g/cm³</u>

<u />

Learn more here:

brainly.com/question/12864420

6 0
2 years ago
Are 22 42 60 a right triangle or not?
Lelechka [254]

Answer:First things first, let's explain what a right triangle is. The definition is very simple and might even seem obvious for those who already know it: a right-angled triangle is a triangle where one and only one of the angles is exactly 90°. The other two angles will clearly be smaller than the right angle because the sum of all angles in a triangle is always 180°.

In a right angled triangle the sides are defined in a special way. The side opposing the right angle is always the biggest in the triangle and receives the name of "hypotenuse". The other two sides are called catheti. The relationship between the hypotenuse and each of the cathetus is a very simple one, as we will see when we will talk about Pythagoras' theorem.

Hypotenuse calculator

If all you want to calculate is the hypotenuse of a right triangle, this page and its right triangle calculator will work just fine. However, we would also recommend to use the specific tool we have developed at Omni Calculators: the hypotenuse calculator. The hypotenuse is opposite the right angle and can be solved by using the Pythagorean theorem. In a right triangle with cathetus a and b and with hypotenuse c, Pythagoras' theorem states that: a² + b² = c².

To solve for c, take the square root of both sides to get c = √(b²+a²). This extension of the Pythagorean theorem can be considered as a "hypotenuse formula". A Pythagorean theorem calculator is also an excellent tool for calculating the hypotenuse.

Let's now solve a practical example of what it would take to calculate the hypotenuse of a right triangle without using any calculators available at Omni:

Obtain the values of a and b,

Square a and b,

Sum up both values: a² + b²,

Take the square root of the result,

The square root will yield a positive and negative result. Since we are dealing with length, disregard the negative result,

The resulting value is the value of the hypotenuse c.

Now let's see what the process would be using one of Omni's calculator, for example, the right triangle calculator on this web page:

Insert the value of a and b into the calculator

Obtain the value of c immediately

As a bonus, you will get the value of the area for such a triangle.

Step-by-step explanation:Hope this helped u also may i have brainlist plz?

4 0
2 years ago
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