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arlik [135]
3 years ago
13

Is the following nuclear equation balanced? No Yes

Chemistry
2 answers:
fredd [130]3 years ago
7 0

Answer:

Yes.

The nuclear equation {226/88 Ra → 222/26 Rn + 4/2 He} is balanced. As we know that an alpha particle is identical to a helium atom. This implies that if an alpha particle is eliminated from an atom's nucleus, an atomic number of 2 and a mass number of 4 is lost.

Therefore, the equation will be reduced to:

226 - 4 = 222

88 - 2 = 86

Hence, the equation is balanced.

Explanation:

navik [9.2K]3 years ago
5 0

Answer:

yes

Explanation:

s]imple yes

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This is going to be a <em>phase </em>change!
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How many grams of KBr is required to prepare 100 mL of<br> 2.0 M KBr solution?
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Answer:

23.8g

Explanation :

Convert 2.0M into mol using mol= concentration x volume

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We can now find grams by using the molar mass of KBr

=119.023 g/mol (Found online) webqc.org

but can be be calculated by using the molecular weight of K and Br found on the periodic table

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3 years ago
Which of the following substances (with specific heat capacity provided) would show the greatest temperature change upon absorbi
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Answer:

Pb is the substance that experiments the greatest temperature change.

Explanation:

The specific heat capacity refers to the amount of heat energy required to raise in 1 degree the temperature of 1 gram of substance. The highest the heat capacity, the more energy it would be required. These variables are related through the equation:

Q = c . m . ΔT

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c is the specific heat capacity (J/g.°C)

m is the mass of the substance

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Since the question is about the change in temperature, we can rearrange the equation like this:

\Delta T = \frac{Q}{c.m}

All the substances in the options have the same mass (m=10.0g) and absorb the same amount of heat (Q=100.0J), so the change in temperature depends only on the specific heat capacity. We can see in the last equation that they are inversely proportional; the lower c, the greater ΔT. Since we are looking for the greatest temperature change, It must be the one with the lowest c, namely, Pb with c = 0.128 J/g°C. This makes sense because Pb is a metal and therefore a good conductor of heat.

Its change in temperature is:

\Delta T = \frac{q}{c.m} = \frac{100.0 J}{0.128 J/g.C . 10.0g } = 78.1

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C. If the mass or length of substance changes it's extensive
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harina [27]
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