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3 years ago

Is the following nuclear equation balanced? No Yes

Chemistry

2 answers:

fredd [130]3 years ago

7 0

Answer:

Yes.

The nuclear equation {226/88 Ra → 222/26 Rn + 4/2 He} is balanced. As we know that an alpha particle is identical to a helium atom. This implies that if an alpha particle is eliminated from an atom's nucleus, an atomic number of 2 and a mass number of 4 is lost.

Therefore, the equation will be reduced to:

226 - 4 = 222

88 - 2 = 86

Hence, the equation is balanced.

Explanation:

navik [9.2K]3 years ago

5 0

Answer:

yes

Explanation:

s]imple yes

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Question 1<br>Dr pepper has an [H+] = 1.4E-5. what is the pH

wariber [46]

PH=-log[H+]
pH=-log(1.4x10^-5)
pH=4.85

3 0

3 years ago

In the following reaction, identify the oxidized species, reduced species, oxidizing agent, and reducing agent. Be sure to answe

gtnhenbr [62]

Answer :

$Cl_2$ is reduced species.

$KI$ is oxidized species.

$Cl_2$ is oxidizing agent.

$KI$ is reducing agent.

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The balanced redox reaction is :

$Cl_2(aq)+2KI(aq)\rightarrow 2KCl(aq)+I_2(aq)$

The half oxidation-reduction reactions are:

Oxidation reaction : $2I^-\rightarrow I_2+2e^-$

Reduction reaction : $Cl_2^++2e^-\rightarrow 2Cl^-$

From this we conclude that the $'KI'$ is the reducing agent that loses an electron to another chemical species in a redox chemical reaction and itself gets oxidized and $'Cl_2'$ is the oxidizing agent that gain an electron to another chemical species in a redox chemical reaction and itself gets reduced.

Thus, $Cl_2$ is reduced species.

$KI$ is oxidized species.

$Cl_2$ is oxidizing agent.

$KI$ is reducing agent.

7 0

4 years ago

Which would be the nobel gas preceding Tin?

Alexxandr [17]

Answer: The noble gas preceding tin is Krypton [Kr].

Explanation: Atomic Number of tin is 50 , Atomic Number of neon is 10, Atomic Number of argon is 18, Atomic Number of krypton is 36 and Atomic Number of xenon is 54.

Atomic number tells us the number of electrons present in the atom.

Thus the electronic configuration of tin according to increasing energy of orbitals is written as $[Kr]4d^105s^25p^2$ .