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ryzh [129]
3 years ago
11

A capacitor is connected to a 9 V battery and acquires a charge Q. What is the charge on the capacitor if it is connected instea

d to an 18 V battery? A capacitor is connected to a 9 V battery and acquires a charge Q. What is the charge on the capacitor if it is connected instead to an 18 V battery? Q Q/2 2Q 4Q
Physics
1 answer:
e-lub [12.9K]3 years ago
3 0

Answer:

Option C is the correct answer.

Explanation:

We have charge stored in a capacitor

           Q = CV

C is the capacitance and V is the voltage.

A capacitor is connected to a 9 V battery and acquires a charge Q.

That is

          Q = C x 9 = 9C

What is the charge on the capacitor if it is connected instead to an 18 V battery

That is

          Q' = C x 18 = 9C x 2 = 2Q

Option C is the correct answer.      

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you place a 0.13kg can of soup and a 0.34kg jar of pickles on the kitchen counter separated by a distance of 0.42m. what is the
Nonamiya [84]

Answer:

1.67×10^-11 N

Explanation:

m1 = 0.13kg

m2 = 0.34kg

d = 0.42m

G = 6.674 × 10 ^−11

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F= (6.674 × 10^ −11×0.13×0.34)/(0.42)²

F = 1.67×10^-11 N

4 0
4 years ago
Examine the lightbulbs in the circuit below. Write a sentence explaining what would happen if lightbulb A burned out. Repeat thi
tatiyna

If the lightbulb A in the circuit shown in the image burned out, the path for the  current to flow is disrupted because one of its terminals is connected direct to the source. So, there will be no current through the lightbulbs B, C, and D, and they will turn off. Similarly it will happen, if the lightbulb D burned out.

If the lightbulb B burned out the current will continue circulating through the lightbulbs A, C, and D, because lightbulb B is connected in parallel. Similarly it will happen, if the lightbulb C burned out.

8 0
4 years ago
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ra1l [238]

Answer:

a) I=0.012\ kg.m^2

b) I=0.012\ kg.m^2

Explanation:

Given that:

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<u>(a)</u>

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I=\frac{1}{12} m.l^2

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I=0.012\ kg.m^2

(b)

<u>Moment of inertia on bending the rod to V-shape of 60 degree angle and axis being perpendicular to the plane of V at the vertex.</u>

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<em>So, the mass and the length of the rod will become half of initial value.</em>

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I=\frac{1}{3} \frac{m}{2} (\frac{l}{2})^2 +\frac{1}{3} \frac{m}{2} (\frac{l}{2})^2

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7 0
3 years ago
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HACTEHA [7]

Answer:

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Rounding to two significant figures, the depth is approximately 2600 m.

5 0
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