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3 years ago

How to calculate depth of sea whan a ship receives sound produced by its fathometer after 3.5 second

Physics

2 answers:

HACTEHA [7]3 years ago

5 0

Answer:

2600 m

Explanation:

A fathometer produces a sound wave and then detects the echo. It takes 3.5 seconds for the echo to reach the ship, so that means it takes half the time (1.75 seconds) to reach the ocean floor.

The speed of sound in seawater is approximately 1500 m/s, so the depth of the ocean at that point is:

d = 1500 m/s × 1.75 s

d = 2625 m

Rounding to two significant figures, the depth is approximately 2600 m.

EleoNora [17]3 years ago

3 0

Answer: the depth is around d = 1.75s*1450m/s = 2537.5 m

Explanation: A fathometer creates a sound pulse and receives the echo of that sound, and in this way, the instrument can obtain a difference of time (the time between the wave is released and received)

Now, knowing that the velocity of the sound in water is around 1450 m/s

now, the lecture is 3.5 seconds, but in this time the wave goes to the bottom and bounces, so the time needed to reach the bottom is half that:

3.5s/2 = 1.75s

then the distance traveled by the wave in that lapse of time is:

d = 1.75s*1450m/s = 2537.5 m

this is a simplification of the math that the device does.

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A student witnesses a flash of lightning and then t=2.5s later the student hears assiciated clap of thunder. (please show work)

frosja888 [35]

Answer:

857.5 m

2.8583×10⁻⁶ seconds

Explanation:

Time taken by the sound of the thunder to reach the student = 2.5 s

Speed of sound in air is 343 m/s

Speed of light is 3×10⁸ m/s

Distance travelled by the sound = Time taken by the sound × Speed of sound in air

⇒Distance travelled by the sound = 2.5×343 = 857.5 m

⇒Distance travelled by the sound = 857.5 m

Time taken by light = Distance the light travelled / Speed of light

$\text{Time taken by light}=\frac{857.5}{3\times 10^8}\\\Rightarrow \text{Time taken by light}=2.8583\times 10^{-6}$

Time taken by light = 2.8583×10⁻⁶ seconds

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3 years ago

Como foi a despedida do bilhete?

Dmitrij [34]

Can you translate to english ?

8 0

2 years ago

You do a certain amount of work on an object initially at rest, and all the work goes into increasing the object’s speed. If you

EleoNora [17]

Answer:

$\sqrt{2}v$

Explanation:

The work done on the object at rest is all converted into kinetic energy, so we can write

$W=\frac{1}{2}mv^2$

Or, re-arranging for v,

$v=\sqrt{\frac{2W}{m}}$

where

v is the final speed of the object

W is the work done

m is the object's mass

If the work done on the object is doubled, we have W' = 2W. Substituting into the previous formula, we can find the new final speed of the object:

$v'=\sqrt{\frac{2W'}{m}}=\sqrt{\frac{2(2W)}{m}}=\sqrt{2}\sqrt{\frac{2W}{m}}=\sqrt{2}v$

So, the new speed of the object is $\sqrt{2}v$ .

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3 years ago

Is the direction of current through a battery always from the negative terminal to the positive one?

rodikova [14]

Answer:

Yes. The current is actually flow of charge and in actual situation electrons flow from negative terminal to positive terminal. But in physics the convention of positive charge flow is used i.e. we take the direction of current from positive to negative terminal.

Explanation:

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3 years ago

Read 2 more answers

If Object C and Object D both have the same momentum, which statement is true? Question 11 options: They both have the same velo

Leya [2.2K]

Answer:

The product of mass times velocity for both objects is the same.

Explanation:

They both have the same velocity. False

They both have the same mass. False: Because two objects of different masses can have the same momentum. The least massive of the two objects will have the greatest kinetic energy.

The product of mass times velocity for both objects is the same. True: Same momentum means that the large mass must have a small velocity; therefore, their product is equal to the small mass times a large velocity.

Mass and velocity is the same for both. False: Based on what was stated for the second option.

7 0

2 years ago