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3 years ago

How to calculate depth of sea whan a ship receives sound produced by its fathometer after 3.5 second

Physics

2 answers:

HACTEHA [7]3 years ago

5 0

Answer:

2600 m

Explanation:

A fathometer produces a sound wave and then detects the echo. It takes 3.5 seconds for the echo to reach the ship, so that means it takes half the time (1.75 seconds) to reach the ocean floor.

The speed of sound in seawater is approximately 1500 m/s, so the depth of the ocean at that point is:

d = 1500 m/s × 1.75 s

d = 2625 m

Rounding to two significant figures, the depth is approximately 2600 m.

EleoNora [17]3 years ago

3 0

Answer: the depth is around d = 1.75s*1450m/s = 2537.5 m

Explanation: A fathometer creates a sound pulse and receives the echo of that sound, and in this way, the instrument can obtain a difference of time (the time between the wave is released and received)

Now, knowing that the velocity of the sound in water is around 1450 m/s

now, the lecture is 3.5 seconds, but in this time the wave goes to the bottom and bounces, so the time needed to reach the bottom is half that:

3.5s/2 = 1.75s

then the distance traveled by the wave in that lapse of time is:

d = 1.75s*1450m/s = 2537.5 m

this is a simplification of the math that the device does.

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A car is running at the speed of 45km/hr see a child 25 meter ahead and suddenly apllies a brakes. If the retradation of the car

kenny6666 [7]

Answer:

The car stops in 7.78s and does not spare the child.

Explanation:

In order to know if the car stops before the distance to the child, you take into account the following equation:

$x=x_o+v_ot-\frac{1}{2}at^2$ (1)

vo: initial speed of the car = 45km/h

a: deceleration of the car = 2 m/s^2

t: time

xo: initial distance to the child = 25m

x: final distance to the child = 0m

It is necessary that the solution of the equation (1) for time t are real.

You first convert the initial speed to m/s, then replace the values of the parameters and solve the quadratic polynomial for t:

$45\frac{km}{h}*\frac{1h}{3600s}*\frac{1000m}{1km}=12.5\frac{m}{s}$

$0=25+12.5t-2t^2\\\\2t^2-12.5t-25=0\\\\t_{1,2}=\frac{-(-12.5)\pm \sqrt{(-12.5)^2-4(2)(-25)}}{2(2)}\\\\t_{1,2}=\frac{12.25\pm 18.87}{4}\\\\t_1=7.78s\\\\t_2=-1.65s$

You take the first value t1 because it has physical meaning.

The solution for t is real, then, the car stops in 7.78s and does not spare the child.

4 0

3 years ago

Explain two reasons why astronomers are continually building larger and larger telescopes. Explain two reasons why astronomers a

Sergio [31]

Answer:

* Larger mirrors collect more light and therefore fainter and more distant objects can have enough intensity to be detected

* arger mirrors decreases the angle of dispersion giving a better resolution of the bodies

Explanation:

Refracting telescopes get bigger every day for two main reasons.

* Larger mirrors collect more light and therefore fainter and more distant objects can have enough intensity to be detected

* the diffraction process for circular apertures is given by

θ = 1.22 λ / D

where d is the diameter of the mirror, therefore having larger mirrors decreases the angle of dispersion giving a better resolution of the bodies

5 0

2 years ago

How is distance related to force in this experiment to mass

Elden [556K]

When distance is increased the amount of force needed will depend on the mass of the object.

5 0

3 years ago

Bone has a Young’s modulus of about

MArishka [77]

Answer:

Explanation:

Bone has a Young’s modulus of about

1.8 × 1010 Pa . Under compression, it can

withstand a stress of about 1.66 × 108 Pa before breaking.

Assume that a femur (thigh bone) is 0.56 m

long, and calculate the amount of compression

this bone can withstand before breakin :).

6 0

3 years ago

In a circus act, a uniform board (length 3.00 m, mass 25.0 kg ) is suspended from a bungie-type rope at one end, and the other e

tester [92]

Answer:

Force of Rope = 122.5 N

Force of Rope = 480.2N

Explanation:

given data

length = 3.00 m

mass = 25.0 kg

clown mass = 79.0 kg

angle = 30°

solution

we get here Force of Rope on with and without Clown that is

case (1) Without Clown

pivot would be on the concrete pillar so Force of Rope will be

Force of Rope × 3m = (25kg)×(9.8ms²)×(1.5m)

solve it and we get

Force of Rope = 122.5 N

and

case (2) With Clown

so here pivot is still on concrete pillar and clown is standing on the board middle and above the centre of mass so Force of Rope will be

Force of Rope × 3m = (25kg+73kg)×(9.8ms²)×(1.5m)

solve it and we get

Force of Rope = 480.2N

4 0

3 years ago