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zloy xaker [14]
4 years ago
8

How to calculate depth of sea whan a ship receives sound produced by its fathometer after 3.5 second

Physics
2 answers:
HACTEHA [7]4 years ago
5 0

Answer:

2600 m

Explanation:

A fathometer produces a sound wave and then detects the echo.  It takes 3.5 seconds for the echo to reach the ship, so that means it takes half the time (1.75 seconds) to reach the ocean floor.

The speed of sound in seawater is approximately 1500 m/s, so the depth of the ocean at that point is:

d = 1500 m/s × 1.75 s

d = 2625 m

Rounding to two significant figures, the depth is approximately 2600 m.

EleoNora [17]4 years ago
3 0

Answer: the depth is around d = 1.75s*1450m/s = 2537.5 m

Explanation:  A fathometer creates a sound pulse and receives the echo of that sound, and in this way, the instrument can obtain a difference of time (the time between the wave is released and received)

Now, knowing that the velocity of the sound in water is around 1450 m/s

now, the lecture is 3.5 seconds, but in this time the wave goes to the bottom and bounces, so the time needed to reach the bottom is half that:

3.5s/2 = 1.75s

then the distance traveled by the wave in that lapse of time is:

d = 1.75s*1450m/s = 2537.5 m

this is a simplification of the math that the device does.

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<span>Frequency of a sound wave is called the pitch. Higher frequencies have a higher pitch and lower frequencies have the opposite. When an ambulance travels by a listener, the frequencies are oscillating rapidly and causing the shrill, loud sounds that emanate from the sirens.</span>
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4 years ago
If grade 7 students learn six periods and if one period is 40 minutes then how many seconds they learn per day
Ludmilka [50]

Answer:

C. 14400

Explanation:

40min × 6 periods = 240mins total.

1 minute = 60 seconds.

240 minutes × 60 = 14400 seconds.

6 0
3 years ago
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How far can light travel in one year?
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The answer is b
300,000 km
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3 years ago
A sample of 5.6 L of a gas is at a pressure of 1.5 atm. If the volume of the gas is compressed to 4.8 L, what will the new press
Effectus [21]

Answer:

1.75atm

Explanation:

According to Boyle's law, the pressure P of a fixed mass of gas is inversely proportional to it's volume V provided that the temperature remains constant.

P\alpha \frac{1}{V}\\hence\\PV=constant

This implies the following;

P_1V_1=P_2V_2=...=P_nV_n............(1) Provided temperature is kept constant.

Given;

P_1=1.5atm\\V_1=5.6L\\P_2=?\\V_2=4.8L

From equation (1), we can write;

P_1V_1=P_2V_2\\hence\\1.5*5.6=P_2*4.8\\\\P_2=\frac{1.5*5.6}{4.8}\\\\P_2=1.75atm

Since all the units are consistent, there is no need for conversion.

3 0
3 years ago
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To push a 26.0 kg crate up a frictionless incline, angled at 25.0° to the horizontal, a worker exerts a force of 209 N parallel
alukav5142 [94]

Answer:

(a) W = +397.1 J

(b) W = -204.6 J

(c) W = 0

(d) W= + 192.5 J

Explanation:

Work (W) is defined as the product of force (F) by the distance (d)the body travels due to this force. :

W= F*d Formula ( 1)

The forces that perform work on an object must be parallel to its displacement.

The forces perpendicular to the displacement of an object do not perform work on it.

The work is positive (W+) if the force has the same direction of movement of the object.  

The work is negative (W-) if the force has the opposite direction of the movement of the object.

Problem development

(a) Work performed by the worker's applied force on the box .

W= 209 N * 1.9 m = +397.1 J

(b) Work performed by the gravitational force on the crate

We calculate the weight component parallel to the displacement of the box:

We define the x-axis in the direction of the inclined plane ,25.0° to the horizontal.

We define the y-axis and in the direction of the plane perpendicular to the inclined plane.

W= m*g=26*9.8= 254.8N : total box weight

Wx= W*sen25.0°= 254.8*sen25.0°= 107.68 N

W = -Wx *d =107.68 N *1.9 m= -204.6 J

(c) Work performed by normal force (N) exerted by the incline on the crate

The force N is perpendicular to the displacement, then:

W=0

(d) Total work done on the crate

W = 397.1 J -204.6 J

W = 192.5 J

4 0
3 years ago
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