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Lisa [10]
3 years ago
14

Students set up an experiment to investigate whether or not a chemical

Chemistry
1 answer:
OlgaM077 [116]3 years ago
4 0

Answer:

open system

Explanation:

it needs to loose mass not gain mass

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Write a balanced equation for the complete combustion of each compound. a. formaldehyde (CH2O(g)) b. heptane (C7H17(l)) c. benze
Yuri [45]

Answer:

a. formaldehyde (CH₂O(g)): CH₂O(g) + O₂(g) → CO₂(g) + H₂O(g)

b. heptane (C₇H₁₇(l)): 4C₇H₁₇(l) + 45O₂(g) → 28CO₂(g) + 34H₂O(g)

c. benzene (C6H6(l))​: C₆H₆(l) + 15/2 O₂(g) → 6CO₂(g) + 3 H₂O(g)

Explanation:

In a reaction of combustion, a hydrocarbon compound (composed of C, H and O) reacts with oxygen gas (O₂). The <u>complete</u> combustion of a hydrocarbon - such as formaldehyde, heptane, and benzene - produces carbon dioxide (CO₂) and water (H₂O).  

Thus, we write the reactants and products for each combustion reaction and then we balance the atoms: C, H, and O.

a. formaldehyde (CH₂O(g)):

CH₂O(g) + O₂(g) → CO₂(g) + H₂O(g)

The chemical equation is already balanced with the coefficients 1: we have the same number of C atoms (1), H (2) and O (3) on both sides of the equation.

b. heptane (C₇H₁₇(l)):

C₇H₁₇(l) + O₂(g) → CO₂(g) + H₂O(g)

Here we have to write a coefficient 28 for CO₂ to balance the C atoms in the products side, and for C₇H₁₇ we write 28/4 = 7. With similar reasoning we found the coefficients for O₂ and H₂O:

4C₇H₁₇(l) + 45O₂(g) → 28CO₂(g) + 34H₂O(g)

c. benzene (C6H6(l))​:

C₆H₆(l) +  O₂(g) → CO₂(g) +  H₂O(g)

First, we write a coefficient of 6 for CO₂ to balance the C atoms. Then, we have to balance H atoms: we write a coefficient 3 in H₂O. Now, we have 12 + 3 = 15 atoms of O on the reactants side. So, we write a half of these number of atoms in the coefficient for O₂: 15/2. We obtain the balanced equation:

C₆H₆(l) + 15/2 O₂(g) → 6CO₂(g) + 3 H₂O(g)

5 0
2 years ago
During the fission of uranium-235, neutrons are released and a small amount of mass is converted to energy. How many neutrons ar
Ksenya-84 [330]
143 neutrons in uranium 235
5 0
3 years ago
Solid sodium metal reacts violently with water, producing heat, hydrogen gas, and sodium hydroxide. How many molecules of hydrog
asambeis [7]

Answer:

4.6 × 10²³ molecules:

Step-by-step solution

You will need a balanced equation with masses, moles, and molar masses, so let's gather the information in one place:

M_r:  22.99

          2Na + 2H₂O ⟶ 2NaOH + H₂

m/g:    35

1. Calculate the <em>moles of Na </em>

Moles of Na = 35 g Na × (1 mol Na/22.99 g Na)

Moles of Na = 1.52 mol Na

2. Calculate the <em>moles of H₂ </em>

Moles of H₂ = 1.52 mol Na × (1 mol H₂/2 mol Na)

Moles of H₂= 0.761 mol H₂

3. Calculate the molecules of H₂

6.022 × 10²³ molecules H₂ = 1 mol H₂

                Molecules of H₂ = 0.761 × (6.022 × 10²³ /1)

                Molecules of H₂ = 4.6 × 10²³ molecules H₂

The reaction forms 4.6 × 10²³ molecules of H₂.

5 0
3 years ago
What is seafood empanada? Explain?
Lyrx [107]
It’s an empanada but instead of one with chicken or cheese or beef or whatever you usually eat empanadas of, it has seafood usually they have shrimp or crab, I hope this helps!
3 0
3 years ago
A 1.2 m aqueous solution of an ionic compound with the formula MX2 has a boiling point of 101.4 celsisus. Calulate the van't Hof
Olegator [25]
The boiling point increase of a solution is a colligative property, which means that it is related with the solvent and the concentration of the solute, as per this formula:

ΔT = i * kb * m

Where, ΔT is the increase in the boiling point, i is the van't Hoof factor (which accounts for the numberof particles that are dissolved), kb is the boiling point and m the molality of the solution.

Gvien the normal boiling point of 100°C for pure water, ΔT = 101.4 °C - 100.0 °C = 1.4 °C.

Kb = 0.512 °C / m

m = 1.2 m

Therefore, i = ΔT / (kb * m) = 1.4°C / (0.512 °C/m * 1.2m) = 2.28

Answer: 2.28
5 0
3 years ago
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