Ask question

Ask question

All categories

2 years ago

13

How does energy travel? Where is the initial source of enenergy in our solar system? What is the process that gives off energy f

rom the sun called?

1 answer:

Brilliant_brown [7]2 years ago

8 0

Jjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj

You might be interested in

You exert 500 N of force down on the earth as you jump into the air. How much force does the earth exert back on you?

zalisa [80]

The same 500N, is the Newton’s Third Law.

6 0

3 years ago

Which one has greater potential energy? An 8 kg rock sitting on a 2.2 m cliff or a 6 kg rock sitting on a 3.2 m cliff.

Evgesh-ka [11]

Answer: The 6 kg rock sitting on a 3.2 m cliff.

Explanation:

The potential energy of an object of mass M that is at a height H above the ground us:

U = M*H*g

where g is the gravitational acceleration:

g = 9.8m/s^2

Then:

"An 8 kg rock sitting on a 2.2 m cliff"

M = 8kg

H = 2.2m

U = 8kg*2.2m*9.8 m/s^2 = 172.48 J

"a 6 kg rock sitting on a 3.2 m cliff"

M = 6kg

H = 3.2m

U = 6kg*3.2m*9.8m/s^2 = 188.16 J

You can see that the 6kg rock on a 3.2m cliff has a larger potential energy.

6 0

3 years ago

Sarah launches her purse straight up in air with a velocity of 30.2m/s<br> How high will it go?

yaroslaw [1]

Answer: 46.53

Explanation:

6 0

3 years ago

35 POINTS! Say If You Drop A Ball from 100 Centimeters. When The ball Bounces, The Ball Does Not Bounce Back Up To 100 Centimete

diamong [38]

some ball when you bounce it it comes back up but according to gravity the energy goes away

8 0

3 years ago

What's the frequency of a wave with a wavelength of 10 and velocity of 200m/s?

uranmaximum [27]

Answer:

$\boxed {\boxed {\sf 20 \ Hz}}$

Explanation:

The frequency of a wave can be found using the following formula.

$f=\frac{v}{\lambda}$

where <em>f</em> is the frequency, <em>v</em> is the velocity/wave speed, and λ is the wavelength.

The wavelength is 10 meters and the velocity is 200 meters per second.

1 m/s can also be written as 1 m*s^-1

Therefore:

$v= 200 \ m*s^{-1} \\\lambda = 10 \ m$

Substitute the values into the formula.

$f=\frac{200 \ m*s^{-1}}{10 \ m}$

Divide and note that the meters (m) will cancel each other out.

$f=\frac{200 \ s^{-1}}{10 \ }$

$f=20 \ s^{-1}$

1 s^-1 is equal to Hertz
Therefore, our answer of 20 s^-1 is equal to 20 Hz

$f= 20 \ Hz$

The frequency of the wave is <u>20 Hertz</u>

7 0

2 years ago