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Crazy boy [7]
3 years ago
13

How does energy travel? Where is the initial source of enenergy in our solar system? What is the process that gives off energy f

rom the sun called?
Physics
1 answer:
Brilliant_brown [7]3 years ago
8 0
Jjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj
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What mass of whole blood (in kg) can be contained in a plastic container whose dimensions are 125 mm by 110 mm by 35 mm? See cha
irakobra [83]

The mass of whole blood is 0.51 kg.

Given data:

The dimensions of container is 125 mmx 110 mm x 35 mm.

From the chart, the density of whole blood at 37 C is,

\rho=\frac{1060kg}{m^3}

The volume of container can be calculated as,

\begin{gathered} V=125mm\times110mm\times35mm \\ V=481250mm^3\times\frac{1m^3}{10^{-9}mm^3} \\ V=4.8125\times10^{-4}m^3 \end{gathered}

The mass of whole blood will be,

\begin{gathered} \rho=\frac{m}{V} \\ \frac{1060kg}{m^3}=\frac{m}{4.8125\times10^{-4}m^3} \\ m=0.51kg \end{gathered}

Thus, the mass of whole blood is 0.51 kg.

4 0
1 year ago
If Earth were twice as far from the sun, the force of gravity attracting the Earth to the Sun would be
posledela
One quater as your moving away more!
3 0
4 years ago
A child sleds down a hill with an acceleration of 2.94 m/s2. If her initial speed is 0.0 m/s and her final speed is 17.5 m/s, ho
hram777 [196]

Answer:

The child will take 5.952 seconds to travel from the top of the hill to the bottom.

Explanation:

Given that the child accelerates uniformly and that both initial (v_{o}) and final speeds (v_{f}), measured in meters per second, and acceleration (a), measured in meters per square second, are known, we proceed to use the following kinematic equation to determine the time taken to travel from the top of the hill to the bottom (t), measured in seconds, is:

t = \frac{v_{f}-v_{o}}{a} (1)

If we know that v_{o} = 0\,\frac{m}{s}, v_{f} = 17.5\,\frac{m}{s} and a = 2.94\,\frac{m}{s^{2}}, then the time taken is:

t = \frac{17.5\,\frac{m}{s}-0\,\frac{m}{s} }{2.94\,\frac{m}{s^{2}} }

t = 5.952\,s

The child will take 5.952 seconds to travel from the top of the hill to the bottom.

8 0
3 years ago
N2 + O2 → 2NO N-N triple bond: 941 kJ/mol O-O double bond: 495 kJ/mol N-O bond: 201 kJ/mol
kiruha [24]

Answer:

\large \boxed{\text{761 kJ}}

Explanation:

You calculate the energy required to break all the bonds in the reactants.

Then you subtract the energy needed to break all the bonds in the products.

                        N₂  +   O₂   ⟶         2NO

                     N≡N  + O=O ⟶       2O-N=O

Bonds:         2N≡N   1O=O        2N-O + 2N=O

D/kJ·mol⁻¹:     941      495           201      607

\begin{array}{rcl}\Delta H & = & \sum{D_{\text{reactants}}} - \sum{D_{\text{products}}}\\& = & 2 \times 941 +1 \times 495 - (2 \times 201 + 2\times 607)\\&=& 2377 - 1616\\&=&\textbf{761 kJ}\\\end{array}\\\text{The enthalpy of reaction is $\large \boxed{\textbf{761 kJ}}$}.

3 0
3 years ago
Convert 13.6g/cm3 into kg/m3​
Wewaii [24]

Answer:

0.000136kg/m3

Explanation:

13.6 / 1000 = 0.0136kg/cm3

0.0136 / 100 = 0.000136kg/m3

5 0
3 years ago
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