A copper coin resting on a piece of cardboard is placed on a beaker as shown in the diagram below. When the cardboard is rapidly
removed, the coin drops into the beaker. The two properties of the coin which best explain its fall are its weight and its-
A: Temperature
B: Density
C: Volume
D: Inertia
A: Temperature
B: Density
C: Volume
D: Inertia
1 answer:
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The maximum mass of a load that can be lifted by the jack and the distance covered are:
m = 160.2 Kg
h = 25 cm
Given that a certain hydraulic jack is used for lifting load. a force of 250N is applied on a small piston with a diameter of 80cm while the diameter of the larger piston is 2.0m.
The parameters given are
= 250
= Area of the small piston = π
= 22/7 x
= 0.5
= ?
= Area of the large piston = π
= π x 1
= 3.14
To calculate the force on the large piston, we will use the below formula
/
=
/
Substitute all the parameters into the equation
250/0.5 = /3.14
= 1570 N
To calculate the maximum mass of a load that can be lifted by the jack, let us apply Newton second law
F = mg
1570 = 9.8m
m = 1570/9.8
m = 160.2 Kg
.(take g=9.81ms^-2)
If the applied force moves through a distance of 25cm, the distance through which the load is lifted will be
/ 0.25
=
/
h
250/0.125 = 1570/3.14h
make h the subject of the formula
6280h = 1570
h = 1570/6280
h = 0.25 m
Therefore, the distance through which the load is lifted is 25 cm
Learn more here: brainly.com/question/13596980