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tangare [24]
3 years ago
10

Which statements describe a situation with a displacement of zero? Check all that apply.

Physics
2 answers:
lakkis [162]3 years ago
8 0

Answer:

1.  running exactly one lap around a racetrack

Explanation:

Displacement is the distance moved in a specified direction. For displacement to be zero the movement must be such that movement it should start and end at the same spot in a specified direction. Unlike other options a racetrack is defined and since it is moving around, it implies that the runner will return to its original position which completes a lap.

Ratling [72]3 years ago
7 0

riding on a Ferris wheel whose entrance and exit are the same

walking around the block, starting from and ending at the same house

running exactly one lap around a racetrack

Explanation:

Displacement is the distance moved in a specific direction. It is a vector quantity which shows magnitude and direction of a moving body.

For a displacement to be zero, it must start and end at point.

  • riding on a Ferris wheel whose entrance and exit are the same
  • walking around the block, starting from and ending at the same house
  • running exactly one lap around a racetrack

Learn more:

Displacement brainly.com/question/5461768

#learnwithBrainly

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At t=0 bullet A is fired vertically with an initial (muzzle) velocity of 450 m/s. When 3s. bullet B is fired upward with a muzzl
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Answer:

At time 10.28 s after A is fired bullet B passes A.

Passing of B occurs at 4108.31 height.

Explanation:

Let h be the height at which this occurs and t be the time after second bullet fires.

Distance traveled by first bullet can be calculated using equation of motion

s=ut+0.5at^2 \\

Here s = h,u = 450m/s a = -g and t = t+3

Substituting

h=450(t+3)-0.5\times 9.81\times (t+3)^2=450t+1350-4.9t^2-29.4t-44.1\\\\h=420.6t-4.9t^2+1305.9

Distance traveled by second bullet

Here s = h,u = 600m/s a = -g and t = t

Substituting

h=600t-0.5\times 9.81\times t^2=600t-4.9t^2\\\\h=600t-4.9t^2 \\

Solving both equations

600t-4.9t^2=420.6t-4.9t^2+1305.9\\\\179.4t=1305.9\\\\t=7.28s \\

So at time 10.28 s after A is fired bullet B passes A.

Height at t = 7.28 s

h=600\times 7.28-4.9\times 7.28^2\\\\h=4108.31m \\

Passing of B occurs at 4108.31 height.

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what is the density to the nearest hundredths, of a metal with a volume of 3.00 cm3 and a mass of 8.13g?
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Since D=M/V, the answer would be 2.7
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