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Jlenok [28]
3 years ago
12

What is the name of the specification that indicates the frequencies that are dedicated for data transmission over cable lines?

Physics
1 answer:
mihalych1998 [28]3 years ago
4 0
The answer to this question is the term
DOCSIS. A DOCSIS or Data Over Cable Service Interface Specification is a telecommunication standard or interface where in an internet was being provided by the use of cables. The advantage of using DOCSIS is that the speed of the internet is faster using this kind of interface.
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assuming birdman flies at height of 72m, how fast should he fly to hit bucket at 63m from start of field. gravity is -9.8m/s^2 n
algol [13]

Answer:

.....Birdman?

Explanation:

7 0
3 years ago
Avery likes to walk 30 feet in 10<br>seconds. What is her speed?​
Sliva [168]

Answer:

If she is walking 30 feet every 10 seconds, that means she is walking 180 feet per minute. Multiply that by the 60 minutes in an hour, means she walks (180x60)= 10,800 feet an hour.

She walks 3 feet a second.

She walks 180 feet a minute.

She walks 10,800 feet an hour.

Explanation:

6 0
3 years ago
radio waves travel at the speed of light, 3 x 10^8 m/s. the wavelength of a radio wave record is 200,000,000 hz is?
ludmilkaskok [199]

Answer:

1.5m

Explanation:

Speed of waves is given as the product of the wavelength and frequency. Sometimes when frequency is not given but the period is given, we get the frequency as the reciprocal of the period. The speed of waves is given in m/s, wavelength in m while frequency in Hz.

Speed, s= fw and making w the subject of formula,

w=\frac {s}{f}

Substituting 300, 000, 000 m/s for s and 200, 000, 000 for f then we obtain that

w=\frac {300000000}{200000000}=1.5 m

6 0
3 years ago
A 2200-kg railway freight car coasts at 4.1 m/s underneath a grain terminal, which dumps grain directly down into the freight ca
777dan777 [17]

Answer:

The answer is "2.41 \times 10^3"

Explanation:

Given:  

m_i = 2000 \ kg \\\\v_i= 4.1 \ \frac{m}{s} \\\\v_f = 3.4 \ \frac{m}{s} \\

Using formula:  

\to m_iv_i = m_fv_f \\\\\to m_f= \frac{m_iv_i}{v_f}

p_i, p_f = system initial and final linear momentum.

V_i, v_f = system original and final linear pace.

m_i = original weight of the car freight.

m_f= car's maximum weight

= \frac{ 2000 \times 4.1}{3.4}\\\\= \frac{ 8.2\times 10^3}{3.4}\\\\= 2.41 \times 10^3

\boxed{m_f = 2.41 \times 10^3}

8 0
2 years ago
A golf ball comes to rest 1.90 seconds after hitting a net. The force of the net slowed the ball down at a rate of 56.3 m/s^2. W
Nadusha1986 [10]

Answer:

The velocity of the ball when it first hit the net is Vi= 106.97 m/s

Explanation:

Vf= 0

Vi= ?

a= 56.3 m/s²

t= 1.9 s

Vf= Vi - a*t

Vi= a*t

Vi= 106.97 m/s

8 0
3 years ago
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