Hello. This question is incomplete. The full question is:
A conducting sphere contains positive charge distributed uniformly over its surface. Which statements about the potential due to this sphere are true? All potentials are measured relative to infinity. (There may be more than one correct choice.)
A) The potential is lowest, but not zero, at the center of the sphere. B) The potential at the center of the sphere is zero. C) The potential at the center of the sphere is the same as the potential at the surface. D) The potential at the surface is higher than the potential at the center. E) The potential at the center is the same as the potential at infinity
Answer:
C) The potential at the center of the sphere is the same as the potential at the surface.
Explanation:
When a conductive sphere has charges that distribute evenly on its surface, it means that its interior has a zero charge cap. As a result, the outside of this sphere has a charge distribution that will be the same if the center of the sphere were charged. In this way, the center and the surface of the sphere become identical in relation to the point charge potential. In other words, this means that the null interior of the sphere has a constant potential that makes the distribution of charges within the sphere exactly equal to the distribution of charges outside the sphere.
Answer:
The answer is "13% and 83%"
Explanation:
The highest power is generated for:
Where voltage, 
, was its calculated maximum power wattage. This same following transcend national stable coins the power output:
The accompanying consecutive values of are done utilizing iteration and an initial value of 0.5 V:
Efficacy is equivalent to:
Currently, 
was calculated with the formula of voltage (4.6.1) as well as the sun is presumed to produce 
of power.
The fulfillment factor is equal to:
fill factor
where open circuit tension of equations (4.6.1) and I = 0. is calculated. The current is equal to the total current of the photo.
Answer:
F = 15.47 N
Explanation:
Given that,
Q = 52 µC
q = 10 µC
d = 55 cm = 0.55 m
We need to find the magnitude of the electrostatic force on q. The formula for the electrostatic force is given by :
So, the magnitude of the electrostatic force is 15.47 N.
Answer:
see below
Explanation:
refractive index of a medium is defined as the ratio of the speed of light in vacuum to the speed of light in medium
critical angle of glass is 42 means that if the angle of incidence inside the glass is 42 degrees, then the angle of refraction in the optically less dense medium will be 90 degrees
hope this helps
