How far an object moves from a reference point is known as<br> type your answer...

Which region is also the spinal column region?<br> vertebral<br> scapular<br> pelvic<br> sternal

NNADVOKAT [17]

Vertebral ...............

6 0

2 years ago

a car with a mass of 1200 kilograms is moving around a circular curve at a uniform velocity of 20 meters per second. the centrip

qaws [65]

Well, first of all, a car moving around a circular curve is not moving
with uniform velocity. The direction of motion is part of velocity, and
the direction is constantly changing on a curve.

The centripetal force that keeps an object moving in a circle is

   Force = (mass of the object) · (speed)² / (radius of the circle)

   F = m s² / r

We want to know the radius, to rearrange the formula to give us
the radius as a function of everything else.

      F   = m s² / r

Multiply each side by 'r': F· r = m · s²

Divide each side by 'F':    r = m · s² / F

We know all the numbers on the right side,
so we can pluggum in:

r =       m    · s² /    F

      r = (1200 kg) · (20 m/s)² / (6000 N) .

I'm pretty sure you can finish it up from here.

5 0

3 years ago

Starting from rest, a 4.0-kg body reaches a speed of 8.0 m/a in 20 s. What is te net force acting on the body?

Strike441 [17]

The guy below is wrong!

F=ma
Where force = mass x acceleration

We dont have acceleration, a= change in velocity divided by the time taken.
a = v (final velocity) - u (initial) / t
a us 8-0 (at rest means u was 0) / 20 = 0.4

Using F=ma

F= mass x acceleration
F= 4 x 0.4
F=1.6 N

5 0

2 years ago

How much work is done if you push a 200 N box across a floor with a force of 50 N for a distance of 20m

vovikov84 [41]

<h2>Answer: 1000 J</h2>

The Work $W$ done by a Force $F$ refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path.

It should be noted that it is a scalar magnitude, and its unit in the International System of Units is the Joule (like energy). Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter:

$1J=(1N)(1m)=Nm$

Now, when the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:

$W=(F)(d)$ (1)

When they are not parallel, both directions form an angle, let's call it $\alpha$ . In that case the expression to calculate the Work is:

$W=Fdcos{\alpha}$ (2)

For example, in order to push the 200 N box across the floor, you have to apply a force along the distance $d$ to overcome the resistance of the weight of the box (its 200 N).

In this case both <u>(the force and the distance in the path) are parallel</u>, so the work $W$ performed is the product of the force exerted to push the box $F=50N$ by the distance traveled $d$ . as shown in equation (1).