All categories

2 years ago

Which wave has a higher frequency than microwaves but lower frequency than UV waves?

Physics

1 answer:

Effectus [21]2 years ago

3 0

Answer:

Infrared

Visible light

Explanation:

Electromagnetic waves are waves consisting of oscillations of the electric and the magnetic field in a plane perpendicular to the direction of motion of the wave.

Electromagnetic waves travel in a vacuum at the speed of light, which is a constant value:

$c=3.00\cdot 10^8 m/s$

Also, electromagnetic waves are classified into 7 different types, depending on their wavelength and frequency. From highest to lowest frequency, we have:

gamma-rays $10^{20}-10^{24} Hz$

x-rays $10^{17}-10^{20}Hz$

ultraviolet $10^{15}-10^{17} Hz$

visible $[4-7.5]\cdot 10^{14} Hz$

infrared $10^{14} Hz$

microwaves $10^{11}-10^{13} Hz$

radio waves

Therefore, from the table we see that both infrared and visible light have higher frequency than microwaves, but lower frequency than UV (ultraviolet).

You might be interested in

Which of your groups should you NOT change anything for? (in other

ella [17]

Answer:

Explanation:

The control is something that is meant to not be changed, the control is a comparison of the experimental.

7 0

3 years ago

A coil has 400 turns and self-inductance 7.50 mH. The current in the coil varies with time according to i = 1680 mA2 cos [πt/(0.

zhannawk [14.2K]

Answer:

(a) 1.58 V

(b) 0.0126 Wb

Solution:

As per the question:

No. of turns in the coil, N = 400 turns

Self Inductance of the coil, L = 7.50 mH = $7.50\times 10^{- 3}\ H$

Current in the coil, i = $1680cos[\frac{\pi t}{0.0250}]$ A

where

$i_{max} = 1680\ mA = 1.680\ A$

Now,

(a) To calculate the maximum emf:

We know that maximum emf induced in the coil is given by:

$e = \frac{Ldi}{dt}$

$e = L\frac{d}{dt}(1680)cos[\frac{\pi t}{0.0250}]$

$e = - 7.50\times 10^{- 3}\times \frac{\pi}{0.0250}\times \frac{d}{dt}(1680)sin[\frac{\pi t}{0.0250}]$

For maximum emf, $sin\theta$ should be maximum, i.e., 1

Now, the magnitude of the maximum emf is given by:

$|e| = 7.50\times 10^{- 3}\times 1680\times 10^{- 3}\times \frac{\pi}{0.0250} = 1.58\ V$

(b) To calculate the maximum average flux,we know that:

$\phi_{m, avg} = L\times i_{max} = 7.50\times 10^{- 3}\times 1.680 = 0.0126\ Wb$

$e = e_{o}sin{\pi t}{0.0250}$

$e = 7.50\times 10^{- 3}\times sin{\pi \times 0.0180}{0.0250} = 2.96\times 10^{- 4} =0.0493\ V$

7 0

3 years ago

Ryan is driving home from work and notices a deer leaping onto the road about 25 m in front of his car. He immediately applies t

Anvisha [2.4K]

Answer:

mu = 0.56

Explanation:

The friction force is calculated by taking into account the deceleration of the car in 25m. This can be calculated by using the following formula:

$v^2=v_0^2+2ax\\$

v: final speed = 0m/s (the car stops)

v_o: initial speed in the interval of interest = 60km/h

= 60(1000m)/(3600s) = 16.66m/s

x: distance = 25m

BY doing a the subject of the formula and replace the values of v, v_o and x you obtain:

$a=\frac{v^2-v_o^2}{2x}=\frac{0m^2/s^2-(16.66m/s)^2}{2(25m)}=-5.55\frac{m}{s^2}$

with this value of a you calculate the friction force that makes this deceleration over the car. By using the Newton second's Law you obtain:

$F_f=ma=(1490kg)(5.55m/s^2)=8271.15N$

Furthermore, you use the relation between the friction force and the friction coefficient:

$F_f= \mu N=\mu mg\\\\\mu=\frac{F_f}{mg}=\frac{8271.15N}{(1490kg)(9.8m/s^2)}=0.56$

hence, the friction coefficient is 0.56

6 0

2 years ago

Which of the following is a terrestrial habitat? A) Pond B) Garden C) Lake D) River

kenny6666 [7]

Answer:

garden

Explanation: All the other habitats are aquatic

8 0

2 years ago

A model rocket is shot directly upward, rises to its maximum height and then returns to its launch position in 10.0 s. Assuming

worty [1.4K]

d. 49.0 m/s

this is your answer. ....OK. ..

please mark me as brainliest. .....

follow me.....my friend. .....

3 0

3 years ago