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3 years ago

Which wave has a higher frequency than microwaves but lower frequency than UV waves?

Physics

1 answer:

Effectus [21]3 years ago

3 0

Answer:

Infrared

Visible light

Explanation:

Electromagnetic waves are waves consisting of oscillations of the electric and the magnetic field in a plane perpendicular to the direction of motion of the wave.

Electromagnetic waves travel in a vacuum at the speed of light, which is a constant value:

$c=3.00\cdot 10^8 m/s$

Also, electromagnetic waves are classified into 7 different types, depending on their wavelength and frequency. From highest to lowest frequency, we have:

gamma-rays $10^{20}-10^{24} Hz$

x-rays $10^{17}-10^{20}Hz$

ultraviolet $10^{15}-10^{17} Hz$

visible $[4-7.5]\cdot 10^{14} Hz$

infrared $10^{14} Hz$

microwaves $10^{11}-10^{13} Hz$

radio waves

Therefore, from the table we see that both infrared and visible light have higher frequency than microwaves, but lower frequency than UV (ultraviolet).

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Tech A says that a relay is a one-way electrical check valve used in alternators to change AC into DC. Tech B says that a relay

Setler [38]

Answer:

The correct answer is from Tech B.

Explanation:

The relay is an electromagnetic device, which is stimulated by a very weak electrical current to open or close a circuit. It functions as a switch controlled by an electrical circuit in which, by means of a coil and an electromagnet, a sequence of one or several contactors is activated that allow to open or close other electrical circuits independent of the one that controls it.

Have a nice day!

7 0

3 years ago

Which of the following are correct statements about the way an atom is put

Ann [662]

Answer:

valenc e shell

Explanation:

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3 years ago

A laser emits a beam of light whose photons all have the same frequency. When the beam strikes the surface of a metal, photoelec

seraphim [82]

Answer:

the no. of ejected electrons per second will increase.

Explanation:

In photoelectric effect, when a light is incident on a metal surface it ejects some electrons from the metal surface. The energy of photon of light must be equal to or greater than the work function of that metal. All the extra energy above the work potential appears as the kinetic energy of the ejected electrons. So, greater he energy of photon greater will be the kinetic energy of the ejected electrons.

A single photon interacts with a single electron and ejects it only if its energy is greater than work function. So, the increase in no. of photons per second means an increase in the intensity of laser beam. And greater no. of photons, will interact with greater no. of electrons. So, <u>the no. of ejected electrons per second will increase.</u>

3 0

3 years ago

V=xf-xi/t solve for t

irina [24]

Answer:

$t=\frac{x_f-x_i}{v}$