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lord [1]
2 years ago
9

The largest of 2 integers is one more than three times the smaller. If the sum of the two integers is 37

Physics
1 answer:
kondor19780726 [428]2 years ago
7 0

Answer:

The two integers are 28 and 9

Explanation:

Let's call the two integers x and y.

We have:

- The largest of the 2 integers is one more than three times the smaller: this means

x = 3y + 1 (1)

- The sum of the two integers is 37:

x + y = 37 (2)

It's a system of two equations that we can solve. Substituting directly (1) into (2),

3y + 1 + y = 37

4y + 1 = 37

4y = 36

y = 9

And so,

x = 3y + 1 = 3(9) + 1 = 27 +1 = 28

So the two integers are 28 and 9.

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a) 0, = -0.33 us

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c) No, The event are not simultaneous i.e they did not occur at the same time, the second even (-0.33 usec) occurs 0.33 usec earlier than the first event.

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a)

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y = 1 / √(1 - 0.49)

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x1 ' = y(x1 - vt1) = 0

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x2 ' = y(x2-vt2)

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= 140m

y2 ' = y2, z2 ' = z2

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using speed of light c as 3*10^8

1.4 [ 0 - (0.7*3*10^8) / (3*10^8)²(100) ]

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b)

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delltaX' = X2' - X1'

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c)

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