I think you mean for those fractions to be multiplied.
In that case, you get
kg - m / sec² = Newton .
Answer:
Percentage increase in the fundamental frequency is
d)-14.02%
Explanation:
As we know that fundamental frequency of the wave in string is given as

now it is given that tension is increased by 30%
so here we will have


now new value of fundamental frequency is given as

now we have

so here percentage change in the fundamental frequency is given as

% change = 14.02%
Answer:
One way to look at this is to consider the forces acting on any point in a string.
For a very small portion of string F = M a must still hold. As M approaches zero the small portion of string would have to approach infinite acceleration if the net force on that portion of string were not zero.
One generally considers the net force acting on the center of mass of an object not the individual forces acting on each infinitesimal mass composing
the object.
"Most gets converted to heat energy" is the one among the following choices given in the question that describes what <span>happens to the energy put into a machine that does not get used to do useful work. The correct option among all the options that are given in the question is the second option or option "B". I hope it helps you.</span>
Answer:
5069.04 seconds
Explanation:
The parameter we are looking for is called the Orbital period of the Hubble Space Telescope.
It is given as:

where r = radius of orbit of Hubble Space Telescope
G = gravitational constant = 
M = Mass of earth
We are given that:
r = radius of the earth + distance of HST from earth
r = 
M = 
Therefore, T will be:


The orbital period of the Hubble Space Telescope is 5069.04 seconds.