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3 years ago

Please help me.. tysvm if you do

Mathematics

1 answer:

FromTheMoon [43]3 years ago

6 0

Answer:

Step-by-step explanation:

"or" means sum, that is all x≤-2 plus all x≥3

≤-2 mens all numbers less than -2 and the -2

≥3 mens all numbers greater than 3 and the 3

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34. Samir can rent a moving truck from

nadezda [96]

The true statement is that renting from Company B will be cheaper if Samir drives the truck 100 miles. Then the correct option is D.

<h3>What is a linear equation?</h3>

The linear equation is given as,

y = mx + c

Where m = the slope of the line

c is the y-intercept of the line.

Let y be the total amount and x be the number of miles.

Samir can rent a moving truck from Company A for $35 plus $0.50 per mile. Then the equation will be

y = 0.5x + 35 ....1

Company B for $25 plus $0.70 per mile. then the equation will be

y = 0.7x + 25 ....2

For the same rent, the number of miles will be

0.7x + 25 = 0.5x + 35

0.2x = 10

x = 50 miles

Renting from Company B will be cheaper if Samir drives the truck 100 miles. Then the correct option is D.

Learn more about linear equation on:

brainly.com/question/11897796

#SPJ1

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cint%20t%5E2%2B1%20%5C%20dt" id="TexFormula1" title="\frac{d}{dx} \

Kisachek [45]

Answer:

$\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} \ = \ 2x^5-8x^2+2x-2$

Step-by-step explanation:

$\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} = \ ?$

We can use Part I of the Fundamental Theorem of Calculus:

$\displaystyle\frac{d}{dx} \int\limits^x_a \text{f(t) dt = f(x)}$

Since we have two functions as the limits of integration, we can use one of the properties of integrals; the additivity rule.

The Additivity Rule for Integrals states that:

$\displaystyle\int\limits^b_a \text{f(t) dt} + \int\limits^c_b \text{f(t) dt} = \int\limits^c_a \text{f(t) dt}$

We can use this backward and break the integral into two parts. We can use any number for "b", but I will use 0 since it tends to make calculations simpler.

$\displaystyle \frac{d}{dx} \int\limits^0_{2x} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}$

We want the variable to be the top limit of integration, so we can use the Order of Integration Rule to rewrite this.

The Order of Integration Rule states that:

$\displaystyle\int\limits^b_a \text{f(t) dt}\ = -\int\limits^a_b \text{f(t) dt}$

We can use this rule to our advantage by flipping the limits of integration on the first integral and adding a negative sign.

$\displaystyle \frac{d}{dx} -\int\limits^{2x}_{0} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}$

Now we can take the derivative of the integrals by using the Fundamental Theorem of Calculus.

When taking the derivative of an integral, we can follow this notation:

$\displaystyle \frac{d}{dx} \int\limits^u_a \text{f(t) dt} = \text{f(u)} \cdot \frac{d}{dx} [u]$
where u represents any function other than a variable

For the first term, replace $\text{t}$ with $2x$ , and apply the chain rule to the function. Do the same for the second term; replace

$\displaystyle-[(2x)^2+1] \cdot (2) \ + \ [(x^2)^2 + 1] \cdot (2x)$

Simplify the expression by distributing $2$ and $2x$ inside their respective parentheses.

$[-(8x^2 +2)] + (2x^5 + 2x)$
$-8x^2 -2 + 2x^5 + 2x$

Rearrange the terms to be in order from the highest degree to the lowest degree.

$\displaystyle2x^5-8x^2+2x-2$

This is the derivative of the given integral, and thus the solution to the problem.

6 0

3 years ago

I think of a number. I multiply it by 7. I add 12. The result is 40. What is the number I am thinking of?

julia-pushkina [17]

The number that you are thinking of is 4. To get this answer I did the opposite of how you received your answer.
40 - 12 = 28
28 ÷ 4 = 7
The number that you are thinking of is 4.

8 0

3 years ago

Can someone tell me the answer?

Sedaia [141]

You just have to divide the decimals

7 0

4 years ago

What is the straight distance between point h and j on the grid below

vesna_86 [32]

Answer:

Step-by-step explanation:

3 0

3 years ago