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sergey [27]
3 years ago
12

what is the initial velocity of a go-kart traveling at a uniform acceleration of 0.5 m/s^2 for 5s as it slows down to a stop?​

Physics
1 answer:
timurjin [86]3 years ago
8 0

The initial velocity of go-kart is 2.5 m/s.

<u>Explanation:</u>

Here, the uniform acceleration of go-kart is given as 0.5 m/s². Also the time required by it to stop is also given as 5 s. As acceleration is the measure of change in velocity per unit time.

In this case, the velocity should be changed from a value to zero to come to rest. So the initial velocity will be positive value and final velocity is zero.

As we know the values of acceleration, final velocity and time, the initial velocity can be easily determined as follows.

Acceleration = \frac{Final velocity -Initial velocity}{Time}

Since, final velocity is zero, acceleration is 0.5 m/s² and time is 5 s, then,

        -0.5=\frac{-\text {Initial velocity}}{5}

        Initial velocity = 0.5 × 5 = 2.5 m/s.

So the initial velocity of go-kart is 2.5 m/s.

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If it takes a force of 20n to stretch a spring 0.1 meter how much energy does the spring have?​
V125BC [204]

Answer:

The energy stored in the spring would be 1 joule.

Explanation:

hope that helps?

8 0
3 years ago
Answer plzz<br>How do we apply Interval Training to our lower body for a workout?
weqwewe [10]
Interval training is simply alternating short bursts (about 30 seconds) of intense activity with longer intervals (about 1 to 2 minutes) of less intense activity. For instance, if your exercise is walking and you're in good shape, you might add short bursts of jogging into your regular brisk walks.
5 0
3 years ago
What is the acceleration of a softball if it hits the ground with a force 0.50 kg and hits the catchers glove with a force of 25
Rom4ik [11]

Acceleration of the ball is 50 m/s^2

Explanation:

The acceleration of the ball can be found by using Newton's second law of motion, which states that the net force acting on an object is equal to the product between the mass of the object and its acceleration:

F=ma

where

F is the net force

m is the mass

a is the acceleration

For the ball in this problem, we have

m = 0.50 kg (mass)

F = 25 N (force)

thereofre, the acceleration of the ball is

a=\frac{F}{m}=\frac{25}{0.50}=50 m/s^2

Learn more about Newton's second law:

brainly.com/question/3820012

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5 0
3 years ago
In the combo circuit diagrammed, R1 = 19.2 Ω, R2 = 20.7 Ω, and R3 = 25.8 Ω. Find the equivalent resistance of the circuit.
garik1379 [7]

Answer:

Equivalent resistance: 13.589 Ω

Explanation:

R series = R1 + R2 + R3 ...

\frac{1}{R_{eq} } = \frac{1}{R1} +\frac{1}{R2} +\frac{1}{R3} ...

Find the equivalent resistance of the right branch of the circuit:

R_{eq}  = R_{2} +R_{3} \\R_{eq} = 20.7 + 25.8 = 46.5 ohms

\frac{1}{R_{eq} } = \frac{1}{19.2} +\frac{1}{46.5}\\\\\frac{1}{R_{eq} } = 0.0735887097\\\\R_{eq} = 13.5890411

6 0
2 years ago
A ship sets sail from Rotterdam, The Netherlands, heading due north at 8.00 m/s relative to the water. The local ocean current i
Nuetrik [128]

Answer:

The velocity of the ship relative to the earth V = 9.05 \frac{m}{s}

Explanation:

The local ocean current is  = 1.52 m/s

Direction \theta = 40°

Velocity component in X - direction V_{x} = 1.52 \cos 40°

V_{x} = 1.164 \frac{m}{s}

Velocity component in Y - direction V_{y} = 8 + 1.52 \sin 40°

V_{y} = 8.97 \frac{m}{s}

The velocity of the ship relative to the earth

V = \sqrt{V_{x}^{2} + V_{y} ^{2}  }

Put the values of V_{x} and V_{y} we get,

⇒ V = \sqrt{1.164^{2} + 8.97 ^{2}  }

⇒ V = 9.05 \frac{m}{s}

This is the velocity of the ship relative to the earth.

7 0
3 years ago
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