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Elena-2011 [213]
3 years ago
8

Notice that in each conversion factor the numerator equals the denominator when units are taken into account. A common error in

dealing with squares is to square the units inside the parentheses while forgetting to square the numbers! QUESTION What is the numerical part of the time conversion factor, apart from units, that would be used to further convert the answer to km/h2
Physics
1 answer:
navik [9.2K]3 years ago
6 0

Answer:

he factor for the temporal part 1.296 107 s² = h²

 m / s² = 12960 km / h²

Explanation:

This is a unit conversion exercise.

In the unit conversion, the size of the object is not changed, only the value with respect to which it is measured is changed, for this reason in the conversion the amount that is in parentheses must be worth one.

In this case, it is requested to convert a measure km/h²

Unfortunately, it is not clearly indicated what measure it is, but the most used unit in physics is   m / s² , which is a measure of acceleration. Let's cut this down

the factor for the distance is 1000 m = 1 km

the factor for time is 3600 s = 1 h

let's make the conversion

        m / s² (1km / 1000 m) (3600 s / 1h)²

note that as time is squared the conversion factor is also squared

        m / s² = 12960 km / h²

the factor for the temporal part 1.29 107 s² = h²

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Answer:

Option (a) is correct.

Explanation:

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4 years ago
1. A huge spool of wire, 10,000 meters long, weighs 81.34 N. You cut off a meter or so and tie it between two posts, 0.660 m apa
WARRIOR [948]

Answer:

The beat frequency is 6.378 Hz.

Explanation:

Given that,

Length of wire = 10000 m

Weight = 81.34 N

Distance = 0.660 m

Tension = 52 N

Frequency = 196 Hz

We need to calculate the mass of the wire

Using formula of weight

W= mg

m = \dfrac{W}{g}

Put the value into the formula

m=\dfrac{81.34}{9.8}

m=8.3\ kg

The mass per unit length of the wire

m_{l}=\dfrac{m}{l}

Put the value into the formula

m_{l}=\dfrac{8.3}{10000}

m_{l}=8.3\times10^{-4}\ kg/m

We need to calculate the frequency in the wire

Using formula of frequency

f_{w}=\dfrac{1}{2l}\sqrt{\dfrac{T}{m_{l}}}

Put the value into the formula

f_{w}=\dfrac{1}{2\times0.660 }\sqrt{\dfrac{52}{8.3\times10^{-4}}}

f_{w}=189.62\ Hz

We need to calculate the beat frequency

Using formula of beat frequency

f_{b}=f_{in}-f_{w}

Put the value into the formula

f_{b}=196-189.622

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Answer:

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Explanation:

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