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3 years ago

23) What is the volume of 2.454 x 1024 atoms of nitrogen gas at STP?

Chemistry

1 answer:

earnstyle [38]3 years ago

3 0

Answer:

d) V = 91.3 L

Explanation:

Given data:

Volume of nitrogen = ?

Temperature = standard = 273.15 K

Pressure = standard = 1 atm

Number of atoms of nitrogen = 2.454×10²⁴ atoms

Solution:

First of all we will calculate the number of moles of nitrogen by using Avogadro number.

1 mole = 6.022×10²³ atoms

2.454×10²⁴ atoms × 1 mol / 6.022×10²³ atoms

0.407×10¹ mol

4.07 mol

Volume of nitrogen:

PV = nRT

1 atm × V = 4.07 mol ×0.0821 atm.L /mol.K ×273.15 K

V = 91.3 atm.L /1 atm

V = 91.3 L

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