How is milk souring a chemical change?

Which of the following relationships concerning solute and solvent are false?

Vedmedyk [2.9K]

D. Nonpolar dissolves in polar

3 0

2 years ago

14 billion years (roughly the age of the universe) to seconds. (Assume there are 365 days in a year.)

fenix001 [56]

Answer:

4.41 × 10¹⁷ Seconds

Explanation:

For this problem we will first find out the number of days in 14 billion years.

Remember that 1 billion is equal to 1,000,000,000 or 10⁹. So, 14 billion years will be written as 14,000,000,000 or 1.4 × 10¹⁰ years.

Therefore, In

1 year there are = 365 years

So, In

1.4 × 10¹⁰ years there will be = X years,

Solving for X,

X = 1.4 × 10¹⁰ years × 365 days / 1 year

X = 5.11 × 10¹² days

Secondly, as there are 24 hours per day and each hour has 60 minutes and each minute has 60 seconds, therefore, the number of seconds per day are calculated as,

Number of Sec/day = 24 × 60 × 60

Number of Sec/day = 86400 sec/day

Hence, If,

1 day has = 86400 seconds

then,

5.11 × 10¹² days will contain = X seconds

Solving for X,

X = 5.11 × 10¹² days × 86400 sec / 1 day

X = 4.41 × 10¹⁷ Seconds

6 0

3 years ago

Moles /Number of Particles Con

Olin [163]

(2.03x10^22)/(6.02x10^23) = .033721 mol Li

I hope this helps, if not, i am sorry

7 0

2 years ago

In acidic aqueous solution, the purple complex ion Co(NH3)5Br2+ undergoes a slow reaction in which the bromide ion is replaced b

kirill115 [55]

Answer:

A) 0.065 M is its molarity after a reaction time of 19.0 hour.

B) In 52 hours $[Co(NH_3)5Br]^{2+}$ will react 69% of its initial concentration.

Explanation:

$Co(NH_3)_5(H_2O)_3+[Co(NH_3)5Br]^{2+}(Purple)(aq)+H_2O(l)\rightarrow [Co(NH_3)_5(H_2O)]^{3+}(Pinkish-orange)(aq)+Br^-(aq)$

The reaction is first order in $[Co(NH_3)5Br]^{2+}$ :

Initial concentration of $[Co(NH_3)5Br]^{2+}$ = $[A_o]=0.100 M$

a) Final concentration of $[Co(NH_3)5Br]^{2+}$ after 19.0 hours= $[A]$

t = 19.0 hour = 19.0 × 3600 seconds ( 1 hour = 3600 seconds)

Rate constant of the reaction = k = $6.3\times 10^{-6} s^{-1}$

The integrated law of first order kinetic is given as:

$[A]=[A_o]\times e^{-kt}$

$[A]=0.100 M\times e^{-6.3\times 10^{-6} s^{-1}\times 19.0\times 3600 s}$

$[A]=0.065 M$

0.065 M is its molarity after a reaction time of 19.0 h.

b)

Initial concentration of $[Co(NH_3)5Br]^{2+}$ = $[A_o]=x$

Final concentration of $[Co(NH_3)5Br]^{2+}$ after t = $[A]=(100\%-69\%) x=31\%x=0.31x$

Rate constant of the reaction = k = $6.3\times 10^{-6} s^{-1}$

The integrated law of first order kinetic is given as:

$[A]=[A_o]\times e^{-kt}$

$0.31x=x\times e^{-6.3\times 10^{-6} s^{-1}\t}$

t = 185,902.06 s = $\frac{185,902.06 }{3600} hour = 51.64 hours$ ≈ 52 hours

In 52 hours $[Co(NH_3)5Br]^{2+}$ will react 69% of its initial concentration.

6 0

3 years ago

This technology makes it easy for doctors to collaborate, which gives patients access to specialists who do not live in their ar

a_sh-v [17]

The answer will be a or d im not really sure but the two of them will work

8 0

3 years ago

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