Mass percentage of a solution is the amount of solute present in 100 g of the solution.
Given data:
Mass of solute H2SO4 = 571.3 g
Volume of the solution = 1 lit = 1000 ml
Density of solution = 1.329 g/cm3 = 1.329 g/ml
Calculations:
Mass of the given volume of solution = 1.329 g * 1000 ml/1 ml = 1329 g
Therefore we have:
571.3 g of H2SO4 in 1329 g of the solution
Hence, the amount of H2SO4 in 100 g of solution= 571.3 *100/1329 = 42.987
Mass percentage of H2SO4 (%w/w) is 42.99 %
i guess its e) Mn (VII)
if it was wrong pls let me knw
Necesito los puntos es urgente
Aluminum foil I think but if not goodluck :)
Answer:
Standard free-energy change at
is 
Explanation:
Oxidation: 
Reduction: 
--------------------------------------------------------------------------------------
Overall: 
Standard cell potential, 
So, 
We know, standard free energy change at
(
): 
where, n is number of electron exchanged during cell reaction, 1F equal to 96500 C/mol
Here n = 2
So, 