Answer:
the value of the equilibrium constant Kp for this reaction is 0.275
Explanation:
Step 1: Data given
Pressure HCl at the equilibrium = 18.0 atm
Pressure H2 at the equilibrium = 25.4 atm
Pressure Cl2 at the equilibrium = 46.4 atm
Step 2: The balanced equation
H2(g) + Cl2(g) → 2 HCl(g)
Step 3: Calculate the value of the equilibrium constant Kp for this reaction
Kp = (pHCl)² / (pH2*pCl2)
Kp = 18.0² / (25.4 * 46.4)
Kp = 324 / 1178.56
Kp = 0.275
the value of the equilibrium constant Kp for this reaction is 0.275
Answer:
B is the answer
Explanation:
Because it a molecular mass of one
Answer is: <span>the mass of the glucose is 81,07 grams.
</span>c(C₆H₁₂O₆) = 0,3 M = 0,3 mol/L.
V(C₆H₁₂O₆) = 1,500 L.
n(C₆H₁₂O₆) = c(C₆H₁₂O₆) · V(C₆H₁₂O₆).
n(C₆H₁₂O₆) = 0,3 mol/L · 1,5 L.
n(C₆H₁₂O₆) = 0,45 mol.
m(C₆H₁₂O₆) = n(C₆H₁₂O₆) · M(C₆H₁₂O₆).
m(C₆H₁₂O₆) = 0,45 mol · 180,156 g/mol.
m(C₆H₁₂O₆) = 81,07 g.
answer: elements are on the periodic table