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rodikova [14]
3 years ago
7

In a two-slit experiment, the slit separation is 3.34 ⋅ 10 − 5 m. The interference pattern is created on a screen that is 3.30 m

away from the slits. If the 7th bright fringe on the screen is 29.0 cm away from the central fringe, what is the wavelength of the light?
Physics
1 answer:
lbvjy [14]3 years ago
8 0

Answer:

The wavelength is  \lambda  = 419 \ nm

Explanation:

From the question we are told that

   The  distance of separation is   d =  3.34 *10^{-5} \ m

   The  distance of the screen is  D  = 3.30 \ m

      The  order of the fringe is  n =  7

     The distance of separation of  fringes is y =  29.0 cm = 0.29 m

   

Generally the wavelength of the light is mathematically represented as

          \lambda  =  \frac{y *  d }{ n  *  D}

substituting values

         \lambda  =  \frac{0.29  *  3.34*10^{-5} }{ 7  *  3.30}

        \lambda  = 4.19*10^{-7}\ m

        \lambda  = 419 \ nm

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