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3 years ago

7

Mrs. Miller is acting a little strange and is pushing as hard as she can against a wall. Using Newton's Laws, what could be say

about the force she is exerting?

2 answers:

deff fn [24]3 years ago

8 0

Newton’s 3rd Law of Motion

Stells [14]3 years ago

4 0

The wall is exerting the same amount of force back at her

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Fifteen identical particles have various speeds: one has a speed of 2.00 m/s, two have speeds of 3.00 m/s, three have speeds 5.0

Tems11 [23]

A. Average speed is weighted mean (1 × 2 + 2 × 3 + 3 × 5 + 4 × 7 + 3 × 9 + 2 × 12.5)/15 = (2 + 6 + 15 + 28 + 27 + 25)/15 = 103/15 = 6.867 b. RMS is square root of 1/15 times sum of squares of speeds Sum of squares is 4 + 9 + 9 + 25 + 25 + 25 + 49 + 49 + 49 + 49 + 81 + 81 + 81 +156.25 + 156.25 = 848.5
c. RMS speed = √(848.5/15) = 7.521
Most likely the speed is the peak in the speed distribution, which is 7.

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3 years ago

if a house had timber walls would the heating bill be higher or lower than a house with fiber board and why

Varvara68 [4.7K]

higher, heat might be able to escape

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4 years ago

As a new electrical technician, you are designing a large solenoid to produce a uniform 0.150-T magnetic field near the center o

Kamila [148]

Answer:

I = 21.94 A

Explanation:

Given that

B= 0.15 T

Number of turns N= 3100

Length L = 57 cm

Diameter ,d= 7 cm

We know that magnetic field in the solenoid given as

$B=\dfrac{\mu_0IN}{L}$

$I=\dfrac{BL}{\mu_0N}$

Now by putting the values

$I=\dfrac{0.15\times 0.57}{4\pi \times 10^{-7}\times 3100}$

I = 21.94 A

Therefore current need to produce 0.15 T magnetic filed is 21.94 A.

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3 years ago

Does anyone know what uranium is???

schepotkina [342]

The answer to your question is "Yes". Great numbers of people ... chemists,
physicists, and common folks alike ... know what Uranium is.

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Uranium is one of the 92 elements that are found to occur in nature.
In the Periodic Table of the Elements, it is Element #92 ... Its atoms
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3 years ago

Read 2 more answers

We showed that the length of the pendulum of period 2.000 seconds on the Earth’s surface was 0.99396 meters. What period would t

Kitty [74]

To solve this problem it is necessary to apply the concepts related to the Period based on gravity and length.

Mathematically this concept can be expressed as

$T= 2\pi \sqrt{\frac{l}{g}}$

Where,

l = Length

g = Gravitational acceleration

First we will find the period that with the characteristics presented can be given on Mars and then we can find the length of the pendulum at the desired time.

The period on Mars with the given length of 0.99396m and the gravity of the moon (approximately $1.62m / s ^ 2)$ will be

$T= 2\pi \sqrt{\frac{l}{g}}$

$T= 2\pi \sqrt{\frac{0.99396}{1.62}}$

$T = 4.921seg$

For the second question posed, it would be to find the length so that the period is 2 seconds, that is:

$T= 2\pi \sqrt{\frac{l}{g}}$

$2= 2\pi \sqrt{\frac{l}{1.62}}$

$l = 0.16414m$

Therefore, we can observe also that the shorter distance would be the period compared to the first result given.

8 0

3 years ago