Which expression is equivalent to 14y+y+3y+14−2?
2 answers:
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Using the relation between velocity, distance and time, it is found that:
- The rate of the plane in still air is of 140 mph.
- The rate of the wind is of 40 mph.
Velocity is <u>distance divided by time</u>, that is:
A plane traveling with the wind travels 900 miles in 5 hours, hence:
The return trip is against the wind and takes 9 hours, hence:
From the first equation, we have that:
[tex]v_w = 180 - 140 = 40{/tex]
Hence:
- The rate of the plane in still air is of 140 mph.
- The rate of the wind is of 40 mph.
More can be learned about the relation between velocity, distance and time at brainly.com/question/24316569