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hram777 [196]
2 years ago
8

If 1 meter is equivalent to 3 28 feet, then approximately how many meters are in one mile?​

Mathematics
1 answer:
gayaneshka [121]2 years ago
4 0

Answer:

Step-by-step explanation:

milă (terestră) = 1.609,344 m = 1.760 yards = 63.360 inches (țoli)

1 „milă romană” (mille passus) = 1.000 (passus) (1 pasus = doi pași, pas dublu) circa. 1.470 - 1.490 m

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Hall travels 99 miles per hour for 6 hours. Find the distance traveled, in miles
Luden [163]

Answer:

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Step-by-step explanation:thjkkmnb

6 0
3 years ago
The figure below shows rectangle ABCD.
kipiarov [429]

Answer: We can find out the missing statement with help of below explanation.

Step-by-step explanation:

We have a rectangle ABCD with diagonals AC and BD ( shown in given figure.)

We have to prove: Diagonals AC and BD bisect each other.

In triangles, AED and BEC.

\angle ADB \cong \angle CBD ( By alternative angle theorem)

AD\cong BC ( Because ABCD is a rectangle)

\angle CAD\cong \angle ACB  ( By alternative angle theorem)

By ASA postulate,\triangle AED\cong \triangle BEC

By CPCTC, BE\cong ED and CE\cong EA

⇒ BE= ED and CE=EA

By the definition of bisector, AC and BD bisect each other.


4 0
3 years ago
Read 2 more answers
Electric charge is distributed over the disk x2 + y2 ≤ 16 so that the charge density at (x, y) is rho(x, y) = 2x + 2y + 2x2 + 2y
professor190 [17]

Answer:

Required total charge is 256\pi coulombs per square meter.

Step-by-step explanation:

Given electric charge is dristributed over the disk,

x^2=y^2\leq 16 so that the charge density at (x,y) is,

\rho (x,y)=2x+2y+2x^2+2y^2

To find total charge on the disk let Q be the total charge and x=r\cos\theta,y=r\sin\theta so that,

Q={\int\int}_Q\rho(x,y) dA                where A is the surface of disk.

=\int_{0}^{2\pi}\int_{0}^{4}(2x+2y+2x^2+2y^2)dA

=\int_{0}^{2\pi}\int_{0}^{4}(2r\cos\theta+2r\sin\theta+2r^2 \cos^{2}\theta+2r^2\sin^2\theta)rdrd\theta

=2\int_{0}^{2\pi}\int_{0}^{4}r^2(\cos\theta+\sin\theta)drd\theta+2\int_{0}^{2\pi}\int_{0}^{4}r^3drd\theta

=\frac{2}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)\Big[r^3\Big]_{0}^{4}d\theta+2\int_{0}^{2\pi}\Big[\frac{r^4}{4}\Big]d\theta

=\frac{128}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)d\theta+128\int_{0}^{2\pi}d\theta

=\frac{128}{3}\Big[\sin\theta-\cos\theta\Big]_{0}^{2\pi}+128\times 2\pi

=\frac{128}{3}\Big[\sin 2\pi-\cos 2\pi-\sin 0+\cos 0\Big]+256\pi

=256\pi

Hence total charge is 256\pi coulombs per square meter.

3 0
3 years ago
A cube has a volume of 2197 m^3. Its surface is to be painted. Each can of paint covers about 40 m^2. How many cans of paint are
Gelneren [198K]
<em>Volume= a³</em>
<em>a=edge</em>
<em>2197 = a³</em>
<em>=> a=13 m</em>
<em>Surface area=6a²=6*13²=6*169=1014 m²</em>
<em>\frac{1014}{40} = 25,35 ≈ 26</em>
<em>=> <u>26 cans needed</u></em>
8 0
3 years ago
Given two central angles in any two circles, the ratio of the arc length to the radius of each corresponding circle is equal if
krok68 [10]
First, we have
s1/r1 = s2/r2

The question also states the fact that
s/2πr = θ/360°

Rearranging the second equation, we have 
s/r = 2πθ/360°

Then we substitute it to the first equation
s1/r1 = 2πθ1/360°
s2/r2 = 2πθ2/360°

which is now 
2πθ1/360° = 2πθ2/360°

By equating both sides, 2π and 360° will be cancelled, therefore leaving 
θ1 = θ2
6 0
3 years ago
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