Answer:
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Step-by-step explanation:thjkkmnb
Answer: We can find out the missing statement with help of below explanation.
Step-by-step explanation:
We have a rectangle ABCD with diagonals AC and BD ( shown in given figure.)
We have to prove: Diagonals AC and BD bisect each other.
In triangles, AED and BEC.
( By alternative angle theorem)
( Because ABCD is a rectangle)
( By alternative angle theorem)
By ASA postulate,
By CPCTC,
and 
⇒ BE= ED and CE=EA
By the definition of bisector, AC and BD bisect each other.
Answer:
Required total charge is
coulombs per square meter.
Step-by-step explanation:
Given electric charge is dristributed over the disk,
so that the charge density at (x,y) is,

To find total charge on the disk let Q be the total charge and
so that,
where A is the surface of disk.



![=\frac{2}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)\Big[r^3\Big]_{0}^{4}d\theta+2\int_{0}^{2\pi}\Big[\frac{r^4}{4}\Big]d\theta](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2%7D%7B3%7D%5Cint_%7B0%7D%5E%7B2%5Cpi%7D%28%5Csin%5Ctheta%2B%5Ccos%5Ctheta%29%5CBig%5Br%5E3%5CBig%5D_%7B0%7D%5E%7B4%7Dd%5Ctheta%2B2%5Cint_%7B0%7D%5E%7B2%5Cpi%7D%5CBig%5B%5Cfrac%7Br%5E4%7D%7B4%7D%5CBig%5Dd%5Ctheta)

![=\frac{128}{3}\Big[\sin\theta-\cos\theta\Big]_{0}^{2\pi}+128\times 2\pi](https://tex.z-dn.net/?f=%3D%5Cfrac%7B128%7D%7B3%7D%5CBig%5B%5Csin%5Ctheta-%5Ccos%5Ctheta%5CBig%5D_%7B0%7D%5E%7B2%5Cpi%7D%2B128%5Ctimes%202%5Cpi)
![=\frac{128}{3}\Big[\sin 2\pi-\cos 2\pi-\sin 0+\cos 0\Big]+256\pi](https://tex.z-dn.net/?f=%3D%5Cfrac%7B128%7D%7B3%7D%5CBig%5B%5Csin%202%5Cpi-%5Ccos%202%5Cpi-%5Csin%200%2B%5Ccos%200%5CBig%5D%2B256%5Cpi)
Hence total charge is
coulombs per square meter.
First, we have
s1/r1 = s2/r2
The question also states the fact that
s/2πr = θ/360°
Rearranging the second equation, we have
s/r = 2πθ/360°
Then we substitute it to the first equation
s1/r1 = 2πθ1/360°
s2/r2 = 2πθ2/360°
which is now
2πθ1/360° = 2πθ2/360°
By equating both sides, 2π and 360° will be cancelled, therefore leaving
θ1 = θ2