Yes, it do, for a short time.
Actually Welcome to the Concept of the Kinematics in real world.
So, as given here, we have to find the Mass of the bus from the given momentum, so we get as,
P = m * V
momentum = mass * velocity
here, P= 152625 kgm/s and v= 11.1 m/s
so substituting we get as,
m = 152625 ÷ 11.1 => 13,750 kg
hence,the mass of the bus is 13,750 kg.
Answer:
Explanation:
wavelength of light = 4 x 10⁻⁷ m
frequency = velocity in air / 4 x 10⁻⁷
= 3 x 10⁸ / 4 x 10⁻⁷
= .75 x 10¹⁵ Hz
= 75 x 10¹³ Hz.
Wave length = 4 x 10⁻⁷ m
= 400 x 10⁻⁹m
400 nm
colour of light having this wavelength in air is violet .
Answer:
at load 13114.85 N beam fail
Explanation:
given data
radius r = 6.7 mm
load = 2710 N
distance = 41 mm
length = 19 mm
to find out
At what load we expect this specimen to fracture
solution
we will first flexural strength that is
flexural strength = load × distance / πr³
flexural strength = 2710 × 41 × / π(6.7 ×)³
flexural strength = 117.592 MPa
we know that for cross section specimen
flexural strength = 3load × distance / 2bd²
put here these value
117.592 × N/m² = 3 load × 41 × / ( 2 × (19×)³)
load = 117.592 × × ( 2 × (19×)³) / ( 3 × 41 × )
load = 13114.85 N
so at load 13114.85 N beam fail